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valentina_108 [34]
3 years ago
5

Say that you put the set of tiles shown below into a bag and conduct a series of trials in which you draw one tile randomly from

the bag, record the color, and replace it. The table below shows the number of times in each set of trials that you drew a blue tile. Round tiles: 5 purple, 6 orange, 2 yellow, 4 red, 1 white, 10 blue, 5 black, 3 green. Trial 1 2 3 4 5 # of Draws 54 36 80 22 75 # of Blues 18 11 20 4 32 Between the theoretical probability that you will draw a blue tile and the experimental probability that you will draw a blue tile, which is greater, and how much greater is it? Express all probabilities as percentages to two decimal places, and express differences by number of percentage points (for example, 12% is 2 percentage points greater than 10%). a. The theoretical probability is 2.78 percentage points greater than the experimental probability. b. The theoretical probability is 1.49 percentage points greater than the experimental probability. c. The experimental probability is 4.06 percentage points greater than the theoretical probability. d. The experimental probability is 2.17 percentage points greater than the theoretical probability.
Mathematics
1 answer:
Karolina [17]3 years ago
8 0

Answer:

letter. c

Step-by-step explanation:

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Reducing Fractions<br> 30/90
fgiga [73]

Answer: 1/3

<u>Divide</u>

30/90÷30/30=1/3

Since we are simplifying fractions we divide the numerator and the denominator by a number the fraction can go into.

We could use 10 then divide by 3. You can also just divide by 30 and get the answer.

Let's try dividing by 10 then 3!

30/90÷10/10=3/9

3/9÷3/3=1/3

As you can see we still get 1/3 when we divide by 3. Even tho you have to divide twice you still get 1/3. That's all that matters.

3 0
4 years ago
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olganol [36]

Answer:

1 / 2

Step-by-step explanation:

- First observe that the fate of the last person is determined the moment either the first or the last seat is selected! This is because the last person will either get the first seat or the last seat. Any other seat will necessarily be taken by the time the last guy gets to 'choose'.

- Since at each choice step, the first or last is equally probable to be taken, the last person will get either the first or last with equal probability: 1/2

- Armed with the key observation, we see that the event that the last person's correct seat is free, is exactly the same as the event that the first person's seat was taken before the last person's seat.

- Well, each person had to make a random choice, was equally likely to choose the first person's seat or the last person's seat - the random chooser exhibits absolutely no preference towards a particular seat. This means that the probability that one seat is taken before the other must be 1/2

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3 years ago
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