The Human Body is made up over

The carbohydrates seen here contain three common elements. What are they?

V125BC [204]

The 3 common elements seen in a majority of carbohydrates or sugars are Carbon, Hydrogen and Oxygen.

6 0

3 years ago

The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61

erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately 6890 years.

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

Available data:

The half-life of C14 is 5730 years
Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g

C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g

λ ⇒ radioactive decay constant = (Ln2)/T₀,₅

T₀,₅ ⇒ The half-life of carbon 14 = 5730 years

T₀ = Time when the organism was alive

T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

λ = 0.0001209

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 = - 0.833

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ = 6889.99 ≅ 6890 years

The bones are approximately 6890 years.

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

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6 0

2 years ago

Wild diploid wheat has seven chromosomes in its pollen. Discuss the major events that had to occur for tetraploid pasta wheat to

lianna [129]

Answer:

Tetraploid wheat evolved by allopolyploidization and subsequent diploid-like behavior due to cytological diploidization

Explanation:

Durum wheat (Triticum durum) or pasta wheat, is a tetraploid wheat species that has 28 chromosomes, i.e., seven pairs in each genome (2n = 4x = 28). Durum wheat was domesticated from wild emmer wheat, which originated by hybridization of two diploid wheat species with 14 chromosomes: Triticum monococcum (genome AA) and one wild progenitor (genome BB). Triticum durum is a typical example of evolution by hybridization and polyploidization, where the resultant tetraploid species has two complete sets of chromosomes. Allopolyploidization is one of the most common types of plant speciation. During meiosis, 28 chromosomes form 14 homologous chromosome pairs, because homologous chromosomes have developed 'restriction of pairing' (i.e., cytological diploidization). The restriction of pairing to fully homologous chromosomes ensures a correct meiotic behavior, which otherwise would be altered due to the high level of homology that still exists among chromosomes from different wheat progenitors.

5 0

2 years ago

What kind of skull is this

nirvana33 [79]

Answer:

The skull is from a fossil skull of Styracosaurus - a horned dinosaur.

Explanation:

This skull image is the skull of a Styracosaurus dinosaur who was a huge dinosaur almost 5 meters or more with the horned present on the skull. This is a fossil skull representation from the fossils.

Styracosaurus was present 75 million years ago during the Cretaceous period who was a completely herbivorous ceratopsian dinosaur.

Thus, the skull is from a fossil skull of Styracosaurus - a horned dinosaur.

6 0

3 years ago

Which is an advantage of a natural-gas-burning power plant over an oil-

finlep [7]

Answer:

C. It uses a renewable resources

7 0

2 years ago