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olga55 [171]
3 years ago
8

The total number of miles Jeremy walked on a hike can be represented by using the formula. If and n represents the total number

of hours walked, what is the total distance Jeremy walked at the end of each of the first three hours?
2 miles, 5 miles, 8 miles
2 miles, 6 miles, 18 miles
2 miles, 3 miles, 4 miles
2 miles, 4 miles, 6 miles
Mathematics
2 answers:
KatRina [158]3 years ago
7 0

Answer:

A) 2 miles, 5 miles, 8 miles

Step-by-step explanation:

Let's get some details cleared.

We're interested in finding how many miles he walked at the end of each hour in a period of 3 hours.

We know what  is, so we can use that as our starting point.

Your answer is A.

Levart [38]3 years ago
5 0

Answer:

A

Step-by-step explanation:

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klemol [59]
You want to make the fractions have the same denominator.
2/3 = 8/12
1/4 = 3/12
now subtract the numerator and keep the denominator the same...
8/12 - 3/12 = 5/12
5 1/2 is the answer
6 0
3 years ago
Read 2 more answers
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

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3 years ago
To fit in an existing frame, the length, x, of a piece of glass must be longer than 12 cm but not longer than 12.2 cm. Which ine
anastassius [24]
Inequality that represents the lengths of the glass:
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Write and solve a system of THREE inequalities that models the situation below.
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Answer:

x = cupcakes

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Step-by-step explanation:

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