.What is four fiths as a decimal?

What is the mean for the data shown in the dot plot? 4 5 6 10

RSB [31]

Answer:

Mean = 6.25

Step-by-step explanation:

Data values: 4, 5, 6, 10

Mean = (Sum of all values)/(Number of values)

Mean = (4 + 5 + 6 + 10)/4

Mean = 25/4

Mean = 6.25

3 0

3 years ago

Read 2 more answers

ANYONE...........help

KATRIN_1 [288]

Answer:

1 cm

Step-by-step explanation:

<u>Sides of the picture added margin:</u>

l = 8 + 2x
w = 5 + 2x

A(margin) = 30 cm²

<u>Solution</u>:

A(margin) = Total area - A(picture)
(8 + 2x)(5 + 2x) - 5*8 = 30
4x² + 10x + 16x + 40 - 40 - 30 = 0
4x² + 26x - 30 = 0
2x² + 13x - 15 = 0
x = (-13 + √(13² + 2*4*15))/4
x = (-13 + 17)/4
x = 1 cm

Note. The other root is ignored as negative.

3 0

3 years ago

Two trains leave Cleveland at the same time. One train travels east and the other travels west. The speed of the westbound train

OlgaM077 [116]

Answer:

The eastbound train travels at 92 mph and the westbound train travels at 96 mph.

Step-by-step explanation:

We know that Velocity = distance / time

If the eastbound train travels at x miles per hour, the westbound train travels at x + 4 mph.

After 3.5 hours, they are 658 miles apart. If we solve for distance the formula given above we have: Distance = velocity x time. We have that the total distance between both trains is 658 miles.

Substituting the values of the problem and solving for x we have

$658 = 3.5x+3.5(x+4)\\658=3.5x+3.5x+14\\644=7x\\92=x$

Thus, the eastbound train travels at 92 mph and the westbound train travels at 96 mph.

6 0

3 years ago

Is correct the number 13

andrey2020 [161]

Yes, the answer is 8.

3 0

3 years ago

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To test whether or not there is a difference between treatments A, B, and C, a sample of 12 observations has been randomly assig

Keith_Richards [23]

Answer:

1. Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

2. D. 36

3. C. 34

4. B. 1.059

5. B. 8.02

Step-by-step explanation:

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part 1

The hypothesis for this case are:

Null hypothesis: $\mu_{A}=\mu_{B}=\mu_{C}$

Alternative hypothesis: Not all the means are equal $\mu_{i}\neq \mu_{j}, i,j=A,B,C$

Part 2

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have $p$ groups and on each group from $j=1,\dots,p$ we have $n_j$ individuals on each group we can define the following formulas of variation:

$SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2$

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

And we have this property

$SST=SS_{between}+SS_{within}$

We need to find the mean for each group first and the grand mean.

$\bar X =\frac{\sum_{i=1}^n x_i}{n}$

If we apply the before formula we can find the mean for each group

$\bar X_A = 27$ , $\bar X_B = 24$ , $\bar X_C = 30$ . And the grand mean $\bar X = 27$

Now we can find the sum of squares between:

$SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2$

Each group have a sample size of 4 so then $n_j =4$

$SS_{between}=SS_{model}=4(27-27)^2 +4(24-27)^2 +4(30-27)^2=72$

The degrees of freedom for the variation Between is given by $df_{between}=k-1=3-1=2$ , Where k the number of groups k=3.

Now we can find the mean square between treatments (MSTR) we just need to use this formula:

$MSTR=\frac{SS_{between}}{k-1}=\frac{72}{2}=36$

D. 36

Part 3

For the mean square within treatments value first we need to find the sum of squares within and the degrees of freedom.

$SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2$

$SS_{error}=(20-27)^2 +(30-27)^2 +(25-27)^2 +(33-27)^2 +(22-24)^2 +(26-24)^2 +(20-24)^2 +(28-24)^2 +(40-30)^2 +(30-30)^2 +(28-30)^2 +(22-30)^2 =306$

And the degrees of freedom are given by:

$df_{within}=N-k =3*4 -3 = 12-3=9$ . N represent the total number of individuals we have 3 groups each one with a size of 4 individuals. And k the number of groups k=3.

And now we can find the mean square within treatments:

$MSE=\frac{SS_{within}}{N-k}=\frac{306}{9}=34$

C. 34

Part 4

The test statistic F is given by this formula:

$F=\frac{MSTR}{MSE}=\frac{36}{34}=1.059$

B. 1.059

Part 5

The critical value is from a F distribution with degrees of freedom in the numerator of 2 and on the denominator of 9 such that we have 0.01 of the area in the distribution on the right.

And we can use excel to find this critical value with this function:

"=F.INV(1-0.01,2,9)"

And we will see that the critical value is $F_{crit}=8.02$

B. 8.02

5 0

3 years ago