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3 years ago

Help please? it’s overdue

Mathematics

2 answers:

Vaselesa [24]3 years ago

5 0

Answer:

The surface area is 76 square yards.

Step-by-step explanation:

A = 2(wl + hl + hw)

2 · (2 · 4 + 5 · 4 + 5 · 2)

denis23 [38]3 years ago

3 0

Answer= 2(wl+hl+hw) What u need to do is do width * length + height * length + height * width (* = multiply)

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Which series of transformations takes the graph of f(x)=3x−8 to the graph of g(x)=−3x+12 ?

kumpel [21]

reflect the graph about the x-axis and translate 4 units down

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2 years ago

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"m divided by 3" is the same as

KonstantinChe [14]

M/3
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the quotient of a number, m, and 3

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3 years ago

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Your friend says that 14.5% is equivilent to 14.5

SCORPION-xisa [38]

14.5% = 0.145 = 145/1000

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3 years ago

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Maddie biked 8 3/4 miles today, and Chase bikes 3 1/2 miles. How many times the length of Chase’s bike ride was Maddie’s bike ri

borishaifa [10]

Answer: 2.5 times

Step-by-step explanation:

Given : The length of Chase’s bike ride= $8\dfrac{3}{4}\ miles$

The length of Maddie’s bike ride= $3\dfrac{1}{2}\ miles$

In improper fraction : Length of Chase’s bike ride= $\dfrac{4(8)+3}{4}\ miles$

$=\dfrac{35}{4}\ miles$

Similarly , Length of Maddie’s bike ride= $\dfrac{7}{2}\ miles$

The number of times the length of Chase’s bike ride was Maddie’s bike ride= $\dfrac{\text{ Length of Chase’s bike ride}}{\text{ Length of Maddie’s bike ride}}$

$=\dfrac{\dfrac{35}{4}}{\dfrac{7}{2}}\\\\=\dfrac{5}{2}=2.5$

Hence, the length of Chase’s bike ride was 2.5 times Maddie’s bike ride.

8 0

2 years ago

Find the distance between (-5,6)and (3,2).

skad [1K]

Answer:

$\displaystyle d = 4\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formulas]: $\displaystyle d = \sqrt{(3+5)^2+(2-6)^2}$
[Distance] [√Radical] (Parenthesis) Add/Subtract: $\displaystyle d = \sqrt{(8)^2+(-4)^2}$
[Distance] [√Radical] Evaluate exponents: $\displaystyle d = \sqrt{64+16}$
[Distance] [√Radical] Add: $\displaystyle d = \sqrt{80}$
[Distance] [√Radical] Simplify: $\displaystyle d = 4\sqrt{5}$

6 0

3 years ago