(x+6)^(1/2)-5=x+1
(x+6)^(1/2)=x+6
((x+6)^(1/2))^2=(x+6)^2
x+6=x^2+12x+36
0=x^2+11x+30
(-11+(11^2-4(1)(30))^(1/2))/2
(-11+((1)^(1/2))/2
(-11+1)/2=-5
(-11-1)/2=-6
((-6)+6)^1/2-5=(-6)+1
(0^(1/2))-5=-5
-6 is non-extraneous
((-5)+6)^1/2-5=(-5)+1
(1^1/2)-5=-4
1-5=-4
-4=-4
-5 is non-extraneous
12 the answer is 12 I know it
The distribution shaped for which the mean and median must be about the same will be:
D. Symmetric
E. uniform
<h3>How to illustrate the information?</h3>
In a symmetric distribution, the median is equal to the mean. The bell-shaped distribution is same as the standard normal distribution.
In a right-skewed distribution, the median is much less than the mean and a bimodal distribution is one with two modes.
Therefore, the correct options are D and E.
Learn more about mean on:
brainly.com/question/1136789
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Hey there!
Edge - a line segment where two <u>verticals</u> meet.
Hope this helps!
