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hoa [83]
3 years ago
9

A digital scale reports a 10 kg weight as weighing 8.975 kg which of the following is true

Mathematics
1 answer:
natima [27]3 years ago
5 0

<em><u>Are the answers these below?</u></em>

<em>A. The scale is accurate but not precise. </em>

<em>B. The scale is precise but not accurate.</em><em> </em>

<em>C. The scale is neither precise nor accurate. </em>

<em>D. The scale is both accurate and precise.</em>

<em>---------------------------------------------------------------------------------------------------------</em>

<em><u>Then you need to tell the difference between accuracy and precision. </u></em>

<em><u> </u></em>

<em><u>Accuracy refers to the closeness of the measure to the real value, while precision, in this case, refers to the level of significant figures that the sacle report. </u></em>

<em><u> </u></em>

<em><u>The fact that the scale reports the number with 4 significant figures means that it is very precise, but the fact that the result is not so close to the real value as the number of significan figures pretend to be, means that the scale is not accurate.</u></em><u><em> </em></u>

<u><em> </em></u>

<u><em>So, the answer is that</em></u>

<u><em> </em></u>B. The scale is precise but not accurate

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The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards (according to GolfWeek). Assume th
Usimov [2.4K]

Answer:

a) f(x) = \frac{1}{25.9}

b) 0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

Step-by-step explanation:

Uniform probability distribution:

An uniform distribution has two bounds, a and b.

The probability of finding a value of at lower than x is:

P(X < x) = \frac{x - a}{b - a}

The probability of finding a value between c and d is:

P(c \leq X \leq d) = \frac{d - c}{b - a}

The probability of finding a value above x is:

P(X > x) = \frac{b - x}{b - a}

The probability density function of the uniform distribution is:

f(x) = \frac{1}{b-a}

The driving distance for the top 100 golfers on the PGA tour is between 284.7 and 310.6 yards.

This means that a = 284.7, b = 310.6.

a. Give a mathematical expression for the probability density function of driving distance.

f(x) = \frac{1}{b-a} = \frac{1}{310.6-284.7} = \frac{1}{25.9}

b. What is the probability the driving distance for one of these golfers is less than 290 yards?

P(X < 290) = \frac{290 - 284.7}{310.6-284.7} = 0.2046

0.2046 = 20.46% probability the driving distance for one of these golfers is less than 290 yards

3 0
2 years ago
Alejandro needs to buy bird seed from the local pet store for his parrots. A
Gnesinka [82]

First take note he only has $20 and the bag he must buy is $12.55. Also the loose seeds are $1.49 per pound.

To solve subtract 12.55 from 20

20-12.55=7.45

So after buying the 10 lb bag he has $7.45 left now divide that by 1.49

7.45/1.49=5

So after buying the 10 lb bag he can also buy 5 lb of the loose seeds!


7 0
3 years ago
Pls help me on this math question.I am really confused
Natali5045456 [20]

Answer:

640 m

Step-by-step explanation:

We can consider 4 seconds to be 1 time unit. Then 8 more seconds is 2 more time units, for a total of 3 time units.

The distance is proportional to the square of the number of time units. After 1 time unit, the distance is 1² × 80 m. Then after 3 time units, the distance will be 3² × 80 m = 720 m.

In the additional 2 time units (8 seconds), the ball dropped an additional

... (720 -80) m = 640 m

_____

<em>Alternate solution</em>

You can write the equation for the proportionality and find the constant that goes into it. If we use seconds (not 4-second intervals) as the time unit, then we can say ...

... d = kt²

Filling in the information related to the first 4 seconds, we have ...

... 80 = k(4)²

... 80/16 = k = 5

Then the distance equation becomes ...

... d = 5t²

After 12 seconds (the first 4 plus the next 8), the distance will be ...

... d = 5×12² = 5×144 = 720 . . . meters

That is, the ball dropped an additional 720 -80 = 640 meters in the 12 -4 = 8 seconds after the first data point.

6 0
3 years ago
the length of diagonal of a rectangular field is 23.7 m and one of its sides is 18.8 m. find the perimeter of the field.​
katen-ka-za [31]

Answer:

Approximately 66.4 Meters

Step-by-step explanation:

So we have a rectangle with a width of 18.8 meters and a diagonal with 23.7 meters. To find the perimeter, we need to find the length first. Since a rectangle has four right angles, we can use the Pythagorean Theorem, where the diagonal is the hypotenuse.

a^2+b^2=c^2

Plug in 18.8 for either <em>a </em>or <em>b. </em>Plug in the diagonal 23.7 for <em>c. </em>

<em />(18.8)^2+b^2=23.7^2\\b^2=23.7^2-18.8^2\\b=\sqrt{23.7^2-18.8^2} \\b\approx14.4 \text{ meters}

Therefore, the length is 14.4 meters. Now, find the perimeter:

P=2l+2w\\P=2(14.4)+2(18.8)\\P=66.4\text{ meters}

7 0
3 years ago
Solve the following formula for m<br><br> C = amt<br><br> m =<br><br> Answer as expression
d1i1m1o1n [39]
M=c/at

Divide both sides by a and t to isolate m. Then the solution is just m=c/at
4 0
3 years ago
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