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Dvinal [7]
2 years ago
10

Solve this please.

3(m - 5) + 11 = - 85" alt="3(m - 5) + 11 = - 85" align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Vikki [24]2 years ago
7 0

Answer:

Bro this some alien hyroglyphics

Step-by-step explanation:

Marrrta [24]2 years ago
6 0

Answer:

m = - 27

Step-by-step explanation:

Given

3(m - 5) + 11 = - 85 ← distribute and simplify left side

3m - 15 + 11 = - 85

3m - 4 = - 85 ( add 4 to both sides )

3m = - 81 ( divide both sides by 3 )

m = - 27

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matrenka [14]
Butttatoe!!!!!!!!!!!!!!!!!!!!!!!!!!!
3 0
3 years ago
Suppose that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage
Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29​%.

Step-by-step explanation:

We are given that in a random selection of 100 colored​ candies, 28​% of them are blue. The candy company claims that the percentage of blue candies is equal to 29​%.

Let p = <u><em>population percentage of blue candies</em></u>

So, Null Hypothesis, H_0 : p = 29%     {means that the percentage of blue candies is equal to 29​%}

Alternate Hypothesis, H_A : p \neq 29%     {means that the percentage of blue candies is different from 29​%}

The test statistics that will be used here is <u>One-sample z-test for</u> <u>proportions</u>;

                         T.S.  =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of blue coloured candies = 28%

           n = sample of colored​ candies = 100

So, <u><em>the test statistics</em></u> =  \frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }

                                    =  -0.22

The value of the z-test statistics is -0.22.

<u>Also, the P-value of the test statistics is given by;</u>

               P-value = P(Z < -0.22) = 1 - P(Z \leq 0.22)

                            = 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, <u><em>so we insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29​%.

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3 years ago
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Answer:

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Step-by-step explanation:

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The correct answer would be D because if there are points at -8 and -2, those are the numbers that are plotted.

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the answer to this problem is 4

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