Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
A reasonable estimate would be 180 students with blue eyes
Answer:
Option ( A ) is the answer at (2, 2), (3, 1), (4, 2)
Step-by-step explanation:
To find the average of numbers you have to add all the numbers and divide by the number of numbers. *confusing*
25 + 25.4 + 25.35 + 26.1 = 101.85
101.85 ÷ 4 = 25.4625
♡ Hope this helped! ♡
❀ 0ranges ❀
9514 1404 393
Answer:
∠Q = 89°
∠R = 123°
∠S = 91°
Step-by-step explanation:
It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.
arc QRS = 2·∠P = 114°
So, ...
arc QR = arc QRS - arc RS = 114° -41° = 73°
The total of the arcs around the circle is 360°, so ...
arc PQ = 360° -arc PS -arc QRS
arc PQ = 360° -137° -114° = 109°
__
∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)
∠Q = 89°
__
∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)
∠R = 123°
__
∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)
∠S = 91°
