You can solve for the velocity and position functions by integrating using the fundamental theorem of calculus:
<em>a(t)</em> = 40 ft/s²
<em>v(t)</em> = <em>v </em>(0) + ∫₀ᵗ <em>a(u)</em> d<em>u</em>
<em>v(t)</em> = -20 ft/s + ∫₀ᵗ (40 ft/s²) d<em>u</em>
<em>v(t)</em> = -20 ft/s + (40 ft/s²) <em>t</em>
<em />
<em>s(t)</em> = <em>s </em>(0) + ∫₀ᵗ <em>v(u)</em> d<em>u</em>
<em>s(t)</em> = 10 ft + ∫₀ᵗ (-20 ft/s + (40 ft/s²) <em>u</em> ) d<em>u</em>
<em>s(t)</em> = 10 ft + (-20 ft/s) <em>t</em> + 1/2 (40 ft/s²) <em>t</em> ²
<em>s(t)</em> = 10 ft - (20 ft/s) <em>t</em> + (20 ft/s²) <em>t</em> ²
Answer:
B is the correct answer
Kevin is K
Daniel is D
Now: K
K = D + 3
3 years ago:
K - 2 = 4(d - 2)
<h2>YOURE WELCOME, PLEASE MARK AS BRAINLIEST AND FOLLOW ME ❤️❤️</h2>
I got you this is the answer Y+6=-1/2(x-4)
64^(4/3)
= 256
32^(3/5)
= 8
625^(3/4)
= 125
81^(5/4)
= 243
