Answer:
Horizontal distance is 142.12 feet.
Step-by-step explanation:
We have,
Velocity of the ball is 38.50 ft/sec. The angle of projection of the ball is 35 degrees.
It is required to find the horizontal distance covered by it before it comes back to the ground on its first bounce. It means we need to find the horizontal range of the projectile. Range of a projectile is given by :
So, the horizontal distance covered by it before it comes back to the ground on its first bounce is 142.12 feet.
Answer:
y= 2x -3
Step-by-step explanation:
Let's rewrite the given equation into the form of y=mx+c, so that we can find the gradient of the line. In this form, m (coefficient of x) is the gradient.
4x -2y= 3
2y= 4x -3
<em>Divide</em><em> </em><em>by</em><em> </em><em>2</em><em> </em><em>throughout</em><em>:</em>
Thus the gradient is 2.
Parallel lines have the same gradient thus the line would also have a gradient of 2.
Substitute m=2 into the equation:
y= 2x +c
To find the value of c, substitute a pair of coordinates.
When x=2, y=1,
1= 2(2) +c
1= 4 +c
c= 1 -4
c= -3
Thus, the equation of the line is y= 2x -3.