Answer:
these three apply:
ΔCBA ≈ ΔFED
ΔBAC ≈ ΔEDF
ΔABC ≈ ΔDEF
Step-by-step explanation:
Answer:
Step-by-step explanation:
By definition, two lines are perpendicular if and only if their slopes are negative reciprocals of each other: , or equivalently, .
Given our linear equation 3x + y = 3 (or y = -3x + 3):
We can find the equation of the line (with a y-intercept of 5) that is perpendicular to y = -3x + 3 by determining the negative reciprocal of its slope, -3, which is .
To test whether this is correct, we can take first slope, , and multiply it with the negative reciprocal slope :
Therefore, we came up with the correct slope for the other line, which is .
Finally, the y-intercept is given by (0, 5). Therefore, the equation of the line that is perpendicular to 3x + y = 3 is:
Answer:
Choice E
Step-by-step explanation:
So the function is
the intial value is where x=0
where x=0, the value of f(0)=3
grouth is 1/3 but it is decay, so it might be correct, or not because it is decay
it is exponential decay
true it is a stretch of the funciton f(x)=(1/3)^x
when x=3, then f(3)=1/9
the true things are
The function shows exponential decay.
The function is a stretch of the function f(x) = (1/3)x .