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Natalka [10]
2 years ago
6

Peggy completed 5/6 of the math homework and Al completed 4/5 of the math homework. Did Peggy or Al complete more of the math ho

mework?
Mathematics
2 answers:
nata0808 [166]2 years ago
6 0

Answer:

I would say that 4/5 is smaller than 5/6 So Al did less than Peggy Correct me if I'm wrong.

Step-by-step explanation:

For the 1st fraction, since 5 × 6 = 30,

4

/5= 4 × 6 =  24

         5 × 6 =    30

Likewise, for the 2nd fraction, since 6 × 5 = 30,

5/6  =  5 × 5    

=25

         6 × 5     30

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

24   25         4   5

30  <  30  

or  5  <6  

xeze [42]2 years ago
3 0
Peggy completed more because more equal parts that are smaller with more shaded means it has to be more.
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16.

points are (0,-3),(2,1),(4,-3)

eq. of line through (0,-3) and (2,1) is

y+3=\frac{1+3}{2-0}(x-0)

or y+3=2x

2x-y=3

as the line is dotted so either < or >.

consider 2x-y>3

put x=0,y=0

0>3

which is not possible .

(0,0) does not satisfy the inequality

Hence shaded region is the required region.

now eq of line through (2,1)and (4,-3) is

y-1=\frac{-3-1}{4-2}(x-2)

y-1=-2(x-2)

y-1=-2x+4

2x+y=5

it is also a  dotted line so either < or >

consider 2x+y<5

put x=0,y=0

0<5

which is true.

so (0,0) satisfy this inequality.

so the two inequalities are

2x-y>3

and 2x+y<5

17.

consider the points (0,4),(2,3),(4,4)

eq. of line through (0,4) and (2,3) is

y-4=\frac{3-4}{2-0}(x-0)

y-4=-1/2(x)

2y-8=-x

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consider x+2y≥8

put x=0,y=0

0≥8

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(0,0) does not satisfy the graph.

which is true as graph lies above the line.

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y-3=\frac{4-3}{4-2}(x-2)

y-3=1/2(x-2)

2y-6=x-2

x-2y=-4

consider x-2y≤-4

put x=0, y=0

0≤-4

which is impossible.

so (0,0) does not satisfy the graph.

so inequality is true as shaded portion is above and left of the line.

so two inequalities are

x+2y≥ 8

and x-2y≤-4

5 0
3 years ago
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