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Andru [333]
2 years ago
15

3 (x + 1) - 5 = 3x - 2 has how many solutions?

Mathematics
1 answer:
marissa [1.9K]2 years ago
7 0

Answer:

Zero Solutions

Step-by-step explanation:

3x+3-5=3x-2

3x-3x= -2+5

0= 3

0 does not equal 3, so zero solutions.

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ONLY ANSWER IF YOU KNOW THE ANSWER JUST FOR POINTS. Thank you! :)
Ksivusya [100]
Since triangle DEF = triangle JKL, m<D = m<J, m<E = m<K, m<F = m<L.
m<F = m<L = 90 degrees
m<K = m<E = 5(m<D)
but m<E + m<D = 90 degrees        [right angled triangle]
5(m<D) + m<D = 90 degrees
6(m<D) = 90 degrees
m<D = 90 / 6 = 15 degrees.
5 0
3 years ago
Read 2 more answers
Find a polynomial function with leading coefficient 1 that has the given zeros, multiplicities, and degree. zero: 1, multiplicit
vfiekz [6]

Polynomial expression for the given  conditions is formulated in the equation

y(x)=1*(x-2)^3(x-0)^2

The polynomial for the conditions with leading coefficient 1 that has the given zeros, multiplicities, and degree. Zero: 2, multiplicity: 3 Zero: 0, multiplicity: 2 Degree: 5 is given as

According to the given condition

The given conditions to write the polynomial equations are as follows

Zero 2  and Multiplicity 3

Zero 0 and Multiplicity 2  

Degree of polynomial expression  = 5

The leading coefficient of polynomial expression = 1

Let us consider the polynomial equation has only one variable and hence in the general form we can write the equation of polynomial as follows

From the general form of polynomial expression as shown in equation (1) we can write

Polynomial expression for the given  conditions is formulated in the equation

y(x)=1*(x-2)^3(x)^2-------(2)

So the polynomial for the conditions given in the question is expressed as

y(x)=1*(x-2)^3(x)^2

For more information on polynomials click on the link below:

brainly.com/question/15702527

#SPJ4

8 0
1 year ago
I have a question if u hay that is 123 IBS and get 12ibs of anything you can thing of and get it to maybe change how it feels ho
ioda
1476 is the answer hope this helps
4 0
3 years ago
What is the mean of this set 18,21,20,14,17
konstantin123 [22]

Answer: 18

Step-by-step explanation:

Add them all up

18+21+20+14+17=90

Divide by 5 since that is how many numbers there are

90/5=18

6 0
3 years ago
Read 2 more answers
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
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