Answer:
Step-by-step explanation:
Let
x= Quantity of donuts
y= Quantity of cupcakes
He bought 3 times as many donuts as cupcakes
Donuts=y= 3x
Donuts=0.50 each
Cupcakes=1.00 each
PxQx + PyQy = 10.00
0.50(x) + 1.00(y) = 10.00
0.50x + 1.00(3x)=10.00
0.50x+3.00x=10.00
3.50x=10.00
Divide both sides by 3.50
x=10.00/3.50
=2.86
y=3x
y=3(2.86)
=8.58
Jamal bought 2.86 donuts and 8.58 cupcakes
Check:
PxQx + PyQy = 10.00
0.50(2.86) + 1.00(8.58) = 10.00
1.43 + 8.58=10.00
10.01=10.00
10.01 approximately 10.00
Area = 2,576 cm
Perimeter = 20 cm
OK to solve this, we have to solve each system presented through elimination or substitution and find which one is equivalent to that of the teacher's!
First let's solve for the teacher's:
-2x+5y=10
-3x+9y=6
Solve by substitution (I think elimination might be easier to do for this one, but I don't really remember 100% sorry!)
Isolate the x (or y) variable in the first equation
-2x+5y=10
-2x=10-5y

Substitute x into the next equation and solve for y
-3(10-5y/2)+9y=6
3*10-5y/2+9y=6
(multiply both sides by 2)
3(10-5y)+18y=12
30-15y+18y=12
30+3y=12
3y=-18
y=-6
Substitute in x
x= -10-5(-6)/2
x=-20
TEACHER'S ANSWER (-20,-6)
GOKU
x-3y=-2
-2x+5y=-7
Do the same as above
Solve for x
x-3y=-2
x=3y-2
Plug in
-2(3y-2)+5y=-7
4-6y+5y=-7
4-y=-7
-y=-11
y=11
x=(3(11)-2)
x=31
GOKU'S ANSWER (31, 11)
SELINA:
-5x+14y=16
-3x+9y=12
One last time!! :)
-5x+14y=16
-5x=16-14y
x=(16-14y)/-5
-3(-(16-14y/5)+9y=12
3*16-14y/5+9y=12
3*16-14y+45y=60
48-42y+45y=60
48+3y=60
3y=12
y=4
x=-(16-14(4))/5
x=8
SELINA'S ANSWER
(8,4)
So neither Goku or Selina got the same answer as the teacher
Answer:
See below for answers and explanations
Step-by-step explanation:
<u>Problem 1:</u>
A standard deck of cards contains 52 cards, consisting of 13 spades. If you select only one randomly, the probability of that occurring would be 13/52 or 1/4. Since there are only 26 red cards in a standard deck, then the probability of selecting a red card would be 26/52 or 1/2. Because the two events are independent of each other, their probabilities are multiplied. Therefore, the probability of selecting a spade, and then replacing it in hopes of drawing a red card is (1/2)(1/4) = 1/8.
<u>Problem 2:</u>
We are selecting a spade and then another spade while NOT replacing the first spade (remember that these events are independent of each other also). This means that the total card count will change by picking up the second card. Therefore, the probability of selecting a spade, followed by another spade, is (13/52)(12/51) = 156/2652 = 1/17.
Train A weighs 181 tons and train B weighs 70 tons.