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ValentinkaMS [17]
2 years ago
5

U0ukj787y8fr7hjhy7 which one

Mathematics
2 answers:
kap26 [50]2 years ago
8 0

Answer:

x=37

Step-by-step explanation:

complementary means when added up they bring 90
so, 53+x=90

x=90-53

x=37

mark me brainliest if it helped pls :)

Sedbober [7]2 years ago
5 0

If ABC and DEF are complementary, then the value of x will be,

90 - ABC = x

90 - 53 = x

x = 37°

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Answer:

(a)  y = 34.27 + 7.79x

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Step-by-step explanation:

Correlation measures how closely two variables are linked.

If two variables are correlated, you can draw a line of best fit on the scatter plot.

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Linear regression is a method for finding the equation of a line of best fit on a scatter plot.

The regression line of y on x is:  y = a + bx

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If b is positive, the variables are positively correlated.

If b is negative, the variables are negatively correlated.

<h3><u>Part (a)</u></h3>

Inputting the data from the table into a calculator and using the statistical function:

a = 34.27272727

b = 7.792207792

Therefore, the linear equation is:

y = 34.27 + 7.79x

<h3><u>Part (b)</u></h3>

The correlation coefficient is the Product Moment Correlation Coefficient (r) and measures the strength of the linear correlation between two variables.

Again, inputting the data from the table into a calculator and using the statistical function:

r = 0.9815741571

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<h3><u>Part (c)</u></h3>

The r value is always between +1 and -1.  The closer it is to +1 or -1, the stronger the correlation between the two variables.

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Therefore, as r is very close to +1, the correlation coefficient suggests a strong, positive correlation.  In the context of the problem, this suggests that as the students spends more time studying, their test scores increase.

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Solve the system by substitution.<br> - 8x + y = -32<br> - 3x – 10 = y<br> (,)
agasfer [191]

Answer:

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Step-by-step explanation:

\begin{bmatrix}-8x+y=-32\\ -3x-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:x\:\mathrm{for}\:-8x+y=-32:\quad x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}x=-\frac{-32-y}{8}\\\begin{bmatrix}-3\left(-\frac{-32-y}{8}\right)-10=y\end{bmatrix}\\\\Simplify\\\begin{bmatrix}\frac{3\left(-32-y\right)}{8}-10=y\end{bmatrix}\\\\\mathrm{Isolate}\:y\:\mathrm{for}\:\frac{3\left(-32-y\right)}{8}-10=y:\quad y=-16\\\\\mathrm{For\:}x=-\frac{-32-y}{8}\\\\\mathrm{Subsititute\:}y=-16\\x=-\frac{-32-\left(-16\right)}{8}\\

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