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Anarel [89]
3 years ago
6

A 2.00 L container of nitrogen had a pressure of 3.20 atm. What volume would be

Chemistry
1 answer:
TiliK225 [7]3 years ago
5 0

Answer:

\large \boxed{\text{6.21 L}}

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

p_{1}V_{1} = p_{2}V_{2}

Data:

\begin{array}{rcrrcl}p_{1}& =& \text{3.20 atm}\qquad & V_{1} &= & \text{2.00 L} \\p_{2}& =& \text{1.03 atm}\qquad & V_{2} &= & ?\\\end{array}

Calculation:  

\begin{array}{rcl}3.20 \times 2.00 & =& 1.03V_{2}\\6.40 & = & 1.03V_{2}\\V_{2} & = &\dfrac{6.40}{1.03}\\\\& = &\textbf{6.21 L}\\\end{array}\\\text{The new volume must be } \large \boxed{\textbf{6.21 L}}

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A 125g metal block at a temperature of 93.2 degrees Celsius was immersed in 100g of water at 18.3 degrees Celsius. Given the spe
ivann1987 [24]

Answer:

Final temperature is 34.2 °C

Explanation:

Given data:

mass of metal = 125 g

temperature of metal = 93.2 °C

mass of water v= 100 g

temperature of water = 18.3 °C

specific heat of meta is = 0.900 j/g. °C

specific heat of water is = 4.186  j/g. °C

final temperature of water and metal = ?

Solution:

Q = m . c . ΔT

ΔT = T2-T1

now we will put the values in equation

Q1 = m . c . ΔT

Q1 = 125 g. 0.900 j/g. °C .93.2°C - T2

Q1 = 112.5 (93.2°C - T2)

Q1 =10,485 - 112.5T2

Q2 = m . c . ΔT

Q2 = 100 . 4.186. (T2- 18.3)

Q2 = 418.6 . (T2- 18.3)

Q2 = 418.6T2 - 7660.38

10,485 - 112.5T2 = 418.6T2 - 7660.38

10,485 +  7660.38 =  418.6T2+  112.5T2

18145.38 = 531.1 T2

T2 = 18145.38/531.1

T2 = 34.2 °C

3 0
3 years ago
An aqueous nacl solution is made using 112 g of nacl diluted to a total solution volume of 1.00 l. calculate the molarity, molal
worty [1.4K]
Q1)
molarity is defined as the number of moles of solute in 1 L of solution.
the NaCl solution volume is 1.00 L
number of moles NaCl  = NaCl mass present / molar mass of NaCl 
NaCl moles = 112 g / 58.5 g/mol = 1.91 mol 
the number of moles of NaCl in 1.00 L of solution is - 1.91 mol 
therefore molarity of NaCl is 1.91 M

Q2) 
molality is defined as the number of moles of solute in 1 kg of solvent.
density is mass per volume. 
density of the solution is 1.08 g/mL. 
therefore mass of the solution is = density x volume 
mass = 1.08 g/mL x 1000 mL = 1080 g
since we have to find the moles in 1 kg of solvent 
mass of solvent = 1080 g - 112 g = 968 g
number of moles of NaCl in 968 g of solvent - 1.91 mol 
therefore number of NaCl moles in 1000 g - (1.91 mol / 968 g) x 1000 g/kg = 1.97 mol/kg
molality of NaCl solution is 1.97 mol/kg


Q3) 
mass percentage is the percentage of mass of solute by total mass of the solution 
mass percentage of solution = mass of solute / total mass of the solution 
mass of solute = 112 g
total mass of solution = 1080 g
mass % of NaCl = 112 g / 1080 g x 100%
therefore mass % of NaCl = 10.4 %
answer is 10.4 %
5 0
3 years ago
How are shadows formed?
Karo-lina-s [1.5K]

Answer:

By something blocking light

Explanation:

6 0
3 years ago
Help please please thanks
9966 [12]

Answer:

the agricultural revolution is the time where people went from mostly being Hunters and Gatherers to mostly farmers, a very long time ago

4 0
3 years ago
Most oxygen in our atmosphere _____. has two oxygen atoms has three oxygen atoms combines with carbon has a single oxygen atom
Morgarella [4.7K]

Answer:

has Two oxygen atoms

Explanation:

Oxygen is a diatomic element hence exists as O2 for majority of its existence in our atmosphere. Although small portion does exist in form of O3 which protects earth from sun's harmful ray, the majority portion of oxygen has O2 which is the oxygen we breathe.

8 0
4 years ago
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