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3 years ago

if salt and sand is mixed with distilled water, what will be the residue and what will be the filtrate?

Chemistry

1 answer:

Gnesinka [82]3 years ago

8 0

Answer:

salt and sand

Explanation:it is what it is

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Water has a density of 1.0 g/cm3. Glycerin, a liquid used in some soaps, has a density of 1.26 g/cm3. If an object sinks in wate

sdas [7]

For an object to sink in something, it's density has to be higher than the object it is in, so if it sinks in water the number has be higher than 1

And to float, and objects density has to be lower than that of the substance it is put in, so it has to be lower than 1.26

So between 1 and 1.26

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3 years ago

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The number of grams per mole of something is known as?

Whitepunk [10]

Answer:

Judging from the wording of he question, you mean units. If that is indeed the case, the answer is g/Mol (grams per mol)

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3 years ago

What is the major divide or ridgeline that separate Virginia's watersheds?

rewona [7]

In Virginia, the continental divide separates the New River from the Roanoake and James River. East of the continental divide, the rivers flow east or south toward the Atlantic Ocean. West of the continental divide, the rivers flow north or west toward the Gulf of Mexico by way of the Ohio and the Mississippi Rivers.

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3 years ago

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Ray Of Light [21]

Can you take picture of the whole question? I can’t see.

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3 years ago

What amount of sucrose (C12H22O11) should be added to 5.83 mol water to lower the vapor pressure of water at 50 °C to 72.0 torr?

Triss [41]

Answer:

The amount of sucrose that must be added is 1.66 moles

Explanation:

Colligative property of lowering vapor pressure has this formula:

Vapor pressure of pure solvent (P°) - Vapor pressure of solution = P° . Xm

We have both vapor pressure (pure solvent and solution9, so let's determine the ΔP

ΔP = 92.6 Torr - 72 Torr = 20.6 Torr

Let's add the data in the formula

20.6 Torr = 92.6 Torr . Xm

Xm = Mole fraction of solute → (mol of solute/ mol of solute + mol of solvent)

Mol of solvent = 5.83 mol (data from the problem)

Therefore Xm = 20.6 Torr / 92.6 Torr → 0.222

Let's find out the moles of solute (our unknown value)

0.22 = moles of solute / moles of solute + 5.83 moles of solvent

0.222 (moles of solute + 5.83 moles of solvent) = moles of solute

0.222 moles of solute + 1.29 moles of solvent = moles of solute

1.29 moles of solvent = moles of solute - 0.222 moles of solute

1.29 moles = 0.778 moles of solute

1.29 / 0.778 = moles of solute → 1.66 moles

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3 years ago