Ask question

Ask question

All categories

3 years ago

12

Work out the surface area of this solid prism.

1 answer:

Aliun [14]3 years ago

7 0

Answer:

264m^2

Step-by-step explanation:

6 by 8 triangle =6*8 for both=48m^2

10 by 9 =10*9=90m^2

6 by 9 =6*9=54m^2

8 by 9 =8*9=72m^2

total=48+90+54+72=264 m^2

You might be interested in

Ok i dont get how to do this will you guys help me im so confused lol

LekaFEV [45]

Ammoni - NH3

nitrification - conversion of ammonia to nitrates

Eutrophication - nutrient overload in the environment

Nitrogen gas - nitrogen fixers

Lightning and bacteria - unusable by most organisms

I hope this helps you, It was the best I could do!

3 0

3 years ago

Solve the system of equations by graphing <br> Y=2<br> Y= 1/2x + 1

docker41 [41]

Answer:

(2,2)

Step-by-step explanation:

first graph the line y=2 (draw a horizontal line through 2 on the y-axis

then graph the line y=1/2x +1 ( plot the point (0,1) and then move up 1 and right 2 or down 1 left 2

then find the point that the lines intersect. That is the solution for the system

6 0

3 years ago

Read 2 more answers

Factoring polynomial. Is there a GCF? Please do number 1

Dahasolnce [82]

I believe the GCF is $5rs^2$

7 0

3 years ago

F(9) = -14. what is the value of f^-1(-14)<br> Please show step by step :)

koban [17]

Answer:

$f^{-1}$ (- 14) = 9

Step-by-step explanation:

f(9) = - 14 maps x = 9 to y = - 14

The inverse maps y = - 14 to x = 9 , that is

$f^{-1}$ (- 14) = 9

8 0

3 years ago

The diagram shows a square ABCD with sides of length 20cm. it also shows a semi circle and an arc circle AB is the diameter of t

Brut [27]

Answer:

Area of Shaded Region $=50\pi$ cm^2$

Area of Semicircle $=50\pi$ cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}}=\dfrac{ \pi}{8}$

Step-by-step explanation:

Area of Shaded Region = Area of Sector - Area of Semicircle

<u>Area of Sector</u>

Radius of the sector =20cm

$=\frac{90}{360}X\pi *20^2\\ =100\pi cm^2$

<u>Area of Semicircle</u>

Since AB is the diameter of the semicircle

Radius of the Semicircle=20/2=10cm

Area of semicircle

$=\frac{\pi r^2}{2}\\ =\frac{\pi *10^2}{2}\\=50\pi cm^2$

Therefore, area of Shaded Region

$=100\pi -50 \pi\\=50\pi$ cm^2$

Area of Square =20 X 20 $=400 cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}} \\=\dfrac{50 \pi}{400} \\=\dfrac{ \pi}{8}$

4 0

3 years ago