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Musya8 [376]
2 years ago
13

The ideal mass for a piece of chocolate is 2.5 ounces. The actual mass for a production can vary by, at most, 0.08

Mathematics
1 answer:
Nady [450]2 years ago
8 0

Answer:

2.42\,oz \leq m_{real} \leq 2.58\,oz

Step-by-step explanation:

The inequality must be the absolute value of the difference between real mass and ideal mass less or equal to 0.08 ounces. That is to say:

|m_{real} - m_{ideal}| \leq 0.08\,oz

|m_{real} - 2.5\,oz| \leq 0.08\,oz

There are two extreme cases:

m_{real,max} - 2.5\,oz = 0.08\,oz and m_{real, min} - 2.5\,oz = -0.08\,oz

m_{real, max} = 2.58\,oz and m_{real,min} = 2.42\,oz

Range of chocolate masses must be:

m_{real, min} \leq m_{real} \leq m_{real,max}

2.42\,oz \leq m_{real} \leq 2.58\,oz

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12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.

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3 years ago
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As a marketing manager, you are tasked with selecting a website to place your advertisement. The following sampled data shows th
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Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Website 1 : 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 377999 / 36 = 10499.9722

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 1 :), s = 110.239865

Website 2 : 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 395197 / 36 = 10977.6944

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 2), s = 132.617995

2.)

Yes, the viewership between the two websites are different with the second website has a higher mean viewership with a mean of 10977.6944.

3.)

The probability of 12000 views per month on each website :

Probability = Mean viewership per month / required viewership

Website 1 :

P(12000) = 10499.9722 / 12000 = 0.8749

Website 2 :

P(12000) = 10977.6944 / 12000 = 0.9148

4.)

More consistent website :

We use the standard deviation value, the higher the standard deviation, the higher the variability :

Website 1 should be more consistent has it has a Lower standard deviation score, hence, should show lower variability than website 2.

5.)

Website suitable for advertisement should be one with higher viewership per month in other to reach a larger audience. Hence, website 2 should be recommended for advertisement.

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2 years ago
Find the sum of 160,-125, and 40.
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The answer is;

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<u>75</u>

7 0
3 years ago
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Larry spent 1/2 of his money on a camera and another 1/8 on a radio. the camera cost $120 more than the radio. how much money di
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Let, his original money = x
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In short, Your Answer would be $240

Hope this helps!
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