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2 years ago

HELP asap the pic saids it all

Mathematics

2 answers:

amid [387]2 years ago

7 0

Answer:

I would say the second boc - at the top right

Step-by-step explanation:

hope this helped

alisha [4.7K]2 years ago

4 0

Second one tell me if im wrong

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Which of the given values is a solution to the equation −11=5t−9

padilas [110]

-11+9= 5t
-2=5t (divide both sides by 5)
t= -2/5

(Mark me the brainliest if this has helped )

6 0

2 years ago

Read 2 more answers

2.<br>Remove the brackets and simplify <br>a) (x + 1) + (x + 2)?

devlian [24]

Step-by-step explanation:

✲ $\text{(x + 1) + (x + 2)}$

Remove the unnecessary brackets :

⇢ $\text{x + 1 + x + 2}$

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⇢ $\text{x + x + 1 + 2}$

⇢ $\text{2x + 3}$

$\red{ \boxed{ \boxed{ \text{Our \: final \: answer : \boxed{ \underline{ \tt{2x + 3}}}}}}}$

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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4 0

2 years ago

Read 2 more answers

How to differentiate ?

Bas_tet [7]

Use the power, product, and chain rules:

$y = x^2 (3x-1)^3$

• product rule

$\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm d(x^2)}{\mathrm dx}\times(3x-1)^3 + x^2\times\dfrac{\mathrm d(3x-1)^3}{\mathrm dx}$

• power rule for the first term, and power/chain rules for the second term:

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(x-1)^2\times\dfrac{\mathrm d(3x-1)}{\mathrm dx}$

• power rule

$\dfrac{\mathrm dy}{\mathrm dx} = 2x\times(3x-1)^3 + x^2\times3(3x-1)^2\times3$

Now simplify.

$\dfrac{\mathrm dy}{\mathrm dx} = 2x(3x-1)^3 + 9x^2(3x-1)^2 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2 \times (2(3x-1) + 9x) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = x(3x-1)^2(15x-2)}$

You could also use logarithmic differentiation, which involves taking logarithms of both sides and differentiating with the chain rule.

On the right side, the logarithm of a product can be expanded as a sum of logarithms. Then use other properties of logarithms to simplify

$\ln(y) = \ln\left(x^2(3x-1)^3\right) \\\\ \ln(y) = \ln\left(x^2\right) + \ln\left((3x-1)^3\right) \\\\ \ln(y) = 2\ln(x) + 3\ln(3x-1)$

Differentiate both sides and you end up with the same derivative:

$\dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac2x + \dfrac9{3x-1} \\\\ \dfrac1y\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \dfrac{15x-2}{x(3x-1)} \times x^2(3x-1)^3 \\\\ \dfrac{\mathrm dy}{\mathrm dx} = x(15x-2)(3x-1)^2$

7 0

1 year ago

Two trains are 500 miles apart when they first enter a collision course. If, after two hours, the distance between them is 300 m

MrRissso [65]

Answer:

The faster train goes 60mph

Step-by-step explanation:

s= speed

s+20 is the faster train.

Then you are given:

200/s+s+20=2

200=2*(2s+20)

4s+40=200

4s=160

s=40 is the slower train

40+20= speed of faster one

s=60 ;)

6 0

2 years ago

Use the sine ratio to find the variable

jek_recluse [69]

Answer: 6.8829172362
Explanation:
sin35=e/12
Multiply 12 on each side
12sin35=e

4 0

2 years ago