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GaryK [48]
3 years ago
11

1,1,2,3,5,8, ______, ______, _______, _________, _______.

Mathematics
2 answers:
jasenka [17]3 years ago
6 0

12 20 32 52 84 hope I helped
zalisa [80]3 years ago
3 0
Add the no befor and the result 13,21,34,55,89 ....
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What’s the difference between x and 4 is greater than 10
daser333 [38]

Answer:

There is a whole range of speeds at which you are allowed to drive, not just one. In cases like this where there is more than one correct answer, we use inequalities, not equations, to represent the situation.

Inequalities are mathematical statements that define a range of values. They are easily recognizable because they contain the symbols <, ≤,>, or ≥.

6 0
3 years ago
500 principal earning 3% compound monthly, after 10 years.
mamaluj [8]

Answer:

D. $674.68

Step-by-step explanation:

We will use the well known equation for compound interest

A = P(1 + \frac{r}{n})^{nt}

Where

  • A is the final total
  • P is the principal amount (starting total)
  • r is the interest rate as a decimal
  • n is the number of times the interest is compounded each year
  • t the number of years

Plugging in what we know from the question:

A = 500(1+\frac{0.03}{12})^{12 \times 10}\\A = 500(1.34935355)\\A = 674.68

So the answer is D.

Hope this helps!

4 0
3 years ago
Multiply the binomials and simplify so that they are in standard form. Show all your work.
tatuchka [14]

Answer: The answer is = 2x^2 -11x-40

Step-by-step explanation: a= 2x, b=5, c= x, d =8

= 2xx + 2x (-8) + 5x +5(-8)

+ (-a)=-a

then simplify =2xx-2 -8x+5x.8

2xx=2x^2

2.8x=16x

5.8=40

=2x - 16x + 5x- 40

8 0
4 years ago
Read 2 more answers
Which option shows the graph of 4y + 8 &lt; -3x
nasty-shy [4]

Answer: On apex it would be answer A the dotted graph with the shaded portion to the bottom left.

Step-by-step explanation:

4 0
3 years ago
The table shows how the compound interest on an investment of $6,000 with an interest rate of 3 34%, compounded annually, grows
PIT_PIT [208]

Answer:

1334

Step-by-step explanation:

4 0
3 years ago
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