Answer:
The answer to your proble I'm slow intercept from is y=-2x+8
Step-by-step explanation:
Mean, because the outliers are limited.
There will be nights when you get more sleep or less sleep than usual, but overall, they will not be far away from the rest of the data you're comparing.
Using the formula (AB +BC) *BC = (DE +CD) *CD
fill i n what is known:
(17 + 4) *4 = (DE +6) *6
21*4 = (DE +6)*6
84 = (DE+6)*6
84/6 = DE+6
14 = DE +6
DE = 14-6
DE = 8
Answer:
The frequency of the note a perfect fifth below C4 is;
B- 174.42 Hz
Step-by-step explanation:
Here we note that to get the "perfect fifth" of a musical note we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have
1.5 × Frequency of note Y = Frequency of C4
1.5 × Y = 261.63
Therefore, Y = 261.63/1.5 = 174.42 Hz.
Answer:
12 (the third one is the greatest common factor of 120 and 84)