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Anni [7]
3 years ago
10

-a^2+46a-480=0 a - ?

Mathematics
2 answers:
Radda [10]3 years ago
8 0
Multiply the equation with -
a^2-46a+480=0
(a-30) (a-16)=0
a=16 or a=30
hope that helps
sattari [20]3 years ago
5 0
a = 30
a = 16

-a² + 46a -480 = 0

(-a + 30) (a -16) = 0
(-a)(a) + (-a)(-16) + 30(a) + 30(-16) = 0
-a² + 16a + 30a -480 = 0
-a² + 46a - 480 = 0

(-a + 30) = 0   ; (a - 16) = 0
-a = -30          ;   a = 16
 a = 30

To check:
a = 30
-(30)² + 46(30) - 480 = 0
-900 + 1380 - 480 = 0
480 - 480 = 0
0 = 0

a = 16
-(16)² + 46(16) - 480 = 0
-256 + 736 - 480 = 0
480 - 480 = 0
0 = 0
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Circle the equivalent expressions: A. 3(2p + 2) B. 12p C. p(3 + 3) + 6 D. 5p + 6 E. 2p + 4p + 6 F. 3 + 6p + 3
Anuta_ua [19.1K]

Answer:

a,e,f

Step-by-step explanation:

a. 6p+6

b.12p

c.6p

d.5p+6

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3 years ago
Need help if anything can show me how to do it in steps !
Elanso [62]

Answer:

x=59/5 or x=11.8 depends on which one you want to do both are true

Step-by-step explanation:

Start with what you are given

angle 4= 5x+6 and angle 3=65 because lines m and n are both parallel angle4=angle3 in other words 5x+6=65

what you want to do is get x by itself.

1. Subtract 6 from both sides

5x+6-6=65-6

5x=59

2. Divide both sides by 5

5x/5=59/5

x=59/5

3. Check to see if you can simplify the fraction and if you teacher wants it in decimals or exact fraction.

x=59/5 or x=11.8 they are the same just ones a decimal the other is left as a fraction

6 0
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Which equation has a graph that is perpendicular to the graph of -x + 6y = -12?
serious [3.7K]

Answer:

c) 6x + y = -52  is required equation perpendicular to the given equation.

Step-by-step explanation:

If the equation is of the form    : y = mx  + C.

Here m = slope of the equation.

Two equations are said to be perpendicular if the product of their respective slopes is -1.

Here, equation 1 :  -x + 6y = -12

or, 6y = -12  + x

or, y = (x/6)  - 2

⇒Slope of line 1 = (1/6)

Now, for equation 2  to be  perpendicular:

Check for each equation:

a. x + 6y = -67       ⇒  6y = -67  - x

or, y = (-x/6)  - (67/6)      ⇒Slope of line 2 = (-1/6)

but \frac{1}{6} \times \frac{-1}{6}  \neq -1

b. x - 6y = -52   ⇒  -6y = -52  - x

or, y = (x/6)  + (52/6)      ⇒Slope of line 2 = (1/6)

but \frac{1}{6} \times \frac{1}{6}  \neq -1

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or, y =y = -52  - 6x      ⇒Slope of line 2 = (-6)

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Hence, 6x + y = -52  is required equation 2.

d. 6x - y = 52  ⇒  -y = 52  - 6x

or, y = 6x   - 52      ⇒Slope of line 2 = (6)

but \frac{1}{6} \times 6  \neq -1

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3 0
3 years ago
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inysia [295]

Answer:

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Step-by-step explanation:

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3) Factors of 4 that add up to -5

4) Factors of -5 that add up to 4

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