Water from rain and snow that travels to streams
Answer:
1. Allele frequency of b = 0.09 (or 9%)
2. Allele frequency of B = 0.91 (0.91%)
3. Genotype frequency of BB = 0.8281 (or 82.81%)
4. Genotype frequency of Bb = 0.1638 (or 16.38%)
Explanation:
Given that:
p = the frequency of the dominant allele (represented here by B) = 0.91
q = the frequency of the recessive allele (represented here by b) = 0.09
For a population in genetic equilibrium:
p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)
(p + q)^2 = 1
Therefore:
p^2 + 2pq + q^2 = 1
in which:
p^2 = frequency of BB (homozygous dominant)
2pq = frequency of Bb (heterozygous)
q^2 = frequency of bb (homozygous recessive)
p^2 = 0.91^2 = 0.8281
2pq = 2(0.91)(0.9) = 0.1638
•The type of fruit or stuff that grows on it like pine cones.
•the color of the leaves (before fall and winter).
•The type of bark on the tree.
Hello. You forgot to put the image so that this question can be answered, but I will describe what the image shows.
The image shows two types of "cups" that have a type of connection between the two. In cup A there is 1 mole of glucose and 1 mole of fructose. In cup B there is 0.1 mol of glucose and 1.5 mol of fructose.
Answer:
A. Solution A to Solution B
Explanation:
Balance is achieved when the "cup" with the lowest concentration of glucose receives glucose from the "cup" with the highest concentration, to the point that the two glasses establish equal concentrations of glucose between them.
We know that cup B has a lower concentration of glucose, which indicates that the movement of this solute was from cup A towards cup B. With this we can conclude that the letter A is the correct answer.
