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nika2105 [10]
3 years ago
5

Simplify this expression: 9x + 8 (6x +2)​

Mathematics
2 answers:
quester [9]3 years ago
6 0

Answer:

9x+64

Step-by-step explanation:

9x+8(6x+2)

9x+64

Sphinxa [80]3 years ago
4 0
9x + 48x + 16
9x + 64
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PLS HELP. here's ss in case anyone got confused last time lol
Varvara68 [4.7K]
Heyyy....I’m still confused. Nah jk but thx for the points lol
4 0
3 years ago
Tangent Line h(t) = sec t / t @ (Pi, 1/pi)
Alex Ar [27]
Take derivitive

note
the derivitive of sec(x)=sec(x)tan(x)
so
remember the quotient rule
the derivitive of \frac{f(x)}{g(x)} = \frac{f'(x)g(x)-g'(x)f(x)}{(g(x))^2}
so

the derivitive of \frac{sec(t)}{t} = \frac{sec(t)tan(t)t-(1)(sec(t))}{t^2}
so now evaluate when t=pi
we get
sec(pi)=-1
tan(pi)=0
we get
\frac{(-1)(0)(pi)-(pi)(-1)}{pi^2}= \frac{pi}{pi^2}= \frac{1}{pi}
slope=1/pi

use slope point form
for
slope=m and point is (x1,y1)
equation is
y-y1=m(x-x1)
slope is 1/pi
point is (pi,1/pi)

y-1/π=1/π(x-π)
times both sides by π
πy-1=x-π
πy=x-π+1
y=(1/π)x-1+(1/π)
or, alternately
-(1/π)x+y=(1/π)-1
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7 0
4 years ago
How do you answer this MATH
raketka [301]
X = 5 or x = 13.

If you need details, please ask!
7 0
3 years ago
Read 2 more answers
How do I graph g(x)=f(x)+5
sashaice [31]
Find the absolute value vertex. In this case, the vertex for y=|x−5|y=|x-5| is (5,0)(5,0).

(5,0)(5,0)

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

(−∞,∞)(-∞,∞)

{x|x∈R}{x|x∈ℝ}

For each xx value, there is one yy value. Select few xx values from the domain. It would be more useful to select the values so that they are around the xx value of the absolute valuevertex.

xy3241506172

8 0
3 years ago
A,B, C and D are the four corners of a rectangular plot marked out on level ground. Given that the bearing of B from A is 40 and
Elden [556K]

Answer:

given - a rectangle ABCD

AB = 40

AC. = 90

BC = ?

in triangle ABC

using Pythagoras theorem

(AB) ² + (BC) ² = (AC) ²

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(BC) ² = 8100 - 1600

(BC) ² = 6500

BC =

20 \sqrt{10}

7 0
2 years ago
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