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oee [108]
3 years ago
10

Question 9 (5 points)

Mathematics
1 answer:
DochEvi [55]3 years ago
8 0

Answer:

D

Step-by-step explanation:

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Pietro is given a test question asking him to show that the sum of two odd integers is
Flura [38]

Answer:  second option Let (2a +1) be an odd number. Let (2b +1) be a different odd number. Because the sum of these two numbers, 2(a + b + 1), is a multiple of 2, it is an even number.

3 0
3 years ago
2.<br> 3 in<br> x in<br> 2 in<br> If the volume of prism is 60 in³,<br> X =
Phoenix [80]

Answer: x=10 in

Step-by-step explanation:

60=3*2*x

60=6*x

x=10 in

5 0
2 years ago
My first expression answer is y=5 -2x How do I plug it into x-y=1 ?? The Y
Lemur [1.5K]

Answer:

All you need to do is make sure the first expression is solved for y (which it is), and then substitute it into the second expression in place of any occurrences of y:

given the second expression:

x - y = 1

We'll replace y with it's value in the first expression:

x - (y) = 1

x - (5 - 2x) = 1

Now we can expand the resulting equation:

x - 5 + 2x = 1

So <em>neither</em> of the answers provided are correct.

You can then solve for x:

x - 5 + 2x = 1

x - 5 + 5 + 2x = 1 + 5

x + 2x = 6

3x = 6

3x/3 = 6/3

x = 2

After that, you can find y by plugging x into either of the two original equations:

y = 5 - 2x

y = 5 - 2(2)

y = 5 - 4

y = 1

8 0
3 years ago
What is the slope and y-intercept
natulia [17]
Slope is 5/4 and y-intercept is -4
hope this helps
8 0
3 years ago
Help I need it now!!<br> T14= 46, and t20= 100, find t3, t7, and tn
Vinil7 [7]

Answer:

t_3 = -53\\\\\\t_7 = -17\\t_n= -80 +9n

Step-by-step explanation:

Arithmetic sequence:

       \sf \boxed{t_n=a+(n-1)d}

Here a is the first term and d is the common difference.

      t_{14}= 6    ⇒  \sf a + 13 d = 46  ------------(I)

     \sf t_{20} = 100 ⇒   a + 19d = 100 ---------(II)

Subtract equation (I) from (II)

(I1)    a + 19d = 100

(II)    a + 13d   =  46

      <u>-    -            -</u>

               6d = 54

                d = 54 ÷ 6

                 \sf \boxed{d = 9}

Substitute d = 9 in equation(I) and find 'a',

    a + 13*9= 46

     a + 117  = 46

              a = 46 - 117

              a = -71

         

\sf t_3 = -71 + 2*9

   = -71 + 18

   = -53

          \sf t_7 = -71 + 6*9

              = -71 + 54

              = -17

\sf t_n= -71 + (n-1)*9

    = -71 + 9*n - 1 *9

    = -71 + 9n - 9

    = -71 - 9 + 9n

     = - 80 + 9n

   

   

5 0
1 year ago
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