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Likurg_2 [28]
2 years ago
7

What is the common factor of 10 and 12

Mathematics
1 answer:
Nostrana [21]2 years ago
7 0

We found the factors and prime factorization of 10 and 12. The biggest common factor number is the GCF number. So the greatest common factor 10 and 12 is 2.

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What is 12a equal to if 4a plus 6b = 10 and 2a-4b=12?
hram777 [196]
12a=x
4a+6b=10
2a+3b=5
2a-4b=12
a-2b=6
2a+3b+1=a-2b
a+5b+1=0
a=-1-5b

2(-1-5b)+3b=5
-2-10b+3b=5
-2-7b=5
-7b=7
7b=-7
b=-1

-1-5*-1=a
-1+5=a
4=a

4*12=48
12a=48

Hope this helps :)
3 0
2 years ago
Read 2 more answers
Consider the accompanying matrix as the augmented matrix of a linear system. State in words the next two elementary row operatio
Lubov Fominskaja [6]

Answer:

The answer is below

Step-by-step explanation:

The next step to solve the system, would be to divide the second row by 3 and we would be left with:  3 * R2

[1 -5 3 0 -2

0 1 -7/3 0 4/3

0 0 1 2 -2]

Then what we will do is multiply row 3 by 7/3 and then subtract it from row 2, that is, R2 - 7/3 * R3, and it would look like this:

[1 -5 3 0 -2

0 1 0 14/3 -10/3

0 0 1 2 -2]

And these would be the next two steps in the process of solving the system.

4 0
3 years ago
Use the proportion. What is 72% of 150
kherson [118]

Answer:

108

Step-by-step explanation:

150x0.72=108

4 0
2 years ago
Read 2 more answers
Un móvil azul de 573 g se encuentra en movimiento sobre un carril metálico. Si sobre el móvil, el resorte ejerce una fuerza haci
ad-work [718]

Answer:

The total mechanical energy is 0.712 J.

Step-by-step explanation:

A blue 573 g mobile is moving on a metal rail. If on the mobile, the spring exerts a force to the right of modulus 0.85 N and in the indicated position the kinetic energy of the mobile-spring system is 0.47 J and its elastic potential energy is 0.242 J. Determine the mechanical energy of the system mobile-spring in the position shown as indicated in the figure.

The total mechanical energy is given by the sum of the kinetic energy and the potential energy.

Kinetic energy = 0.47 J

Potential energy = 0.242 J

The total mechanical energy is

T = 0.47 + 0.242 = 0.712 J

4 0
2 years ago
a circle is centered at the point -3,2) and passes through the point (1,5). The radius of the circle is blank units. The point (
lianna [129]
It's important that you share the complete question.  What is your goal here?  Double check to ensure that you have copied the entire problem correctly.

The general equation of a circle is x^2 + y^2 = r^2.  Here we know that the circle passes thru two points:  (-3,2) and (1,5).  Given that a third point on the circle is (-7, ? ), find the y-coordinate of this third point.


Subst. the known values (of the first point) into this equation:  (-3)^2 + (2)^2 = r^2.  Then 9 + 4 = 13 = r^2.

Let's check this.  Assuming that the equation of this specific circle is 
x^2 + y^2 = r^2 = 13, the point (1,5) must satisfy it.

(1)^2 + (5)^2 = 13 is not true, unfortunately.

(1)^2 + (5)^2 = 1 + 25 = 26 (very different from 13).

Check the original problem.  If it's different from that which you have shared, share the correct version and come back here for further help.



3 0
3 years ago
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