Answer:
yes, the student who has 8 pets.
Step-by-step explanation:
the majority of the class has between 0-4 pets leaving the student with 8 to be the "outlier"
Answer: 47 and 16
Step-by-step explanation:
- Make Two Equations
x + y = 63
x - y = 31
- Set one of the equations equal to one of the variables
x + y = 63
x = 31 + y
- Substitute the equation back into the other one
(31 + y) + y = 63
31 + 2y = 63
2y = 32
y = 16
- Substitute the answer back into the equation
x + y = 63
x + 16 = 63
x = 47
1470 because 0.52 is close to the whole
21 and -4, because -4x21 = -84, and 21+-4 (– 4) = 17
