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cluponka [151]
3 years ago
7

What is 6 1/2 times 77

Mathematics
2 answers:
PSYCHO15rus [73]3 years ago
7 0
500\frac{1}{2}
Hope this helps!
Goshia [24]3 years ago
5 0
The answer is 500 1/2!!!
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Samantha buys a pair of sneakers that were originally $60. They were on sale for 25%
Alex_Xolod [135]

Answer:

$47.70

Step-by-step explanation:

60.00 x .25 = 15  ( so $15.00 off the shoes )

60.00-15.00 = 45.00

45.00 x .06 = 2.70 (2.70 is your sales tax so add that to you sale price )

$45.00 + $2.70 =$47.70 Total

3 0
3 years ago
the graph shows the number of people in an amusement park at different times where our 0 represents 9 a.m. if this trend continu
NNADVOKAT [17]

Answer:

can we see the graph?

Step-by-step explanation:

3 0
3 years ago
The grid you see below is in the shape of a rectangle. What is the area, in square units, of the shaded part?
kherson [118]

Answer:

8 units²

Step-by-step explanation:

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   = 0,5 × 4 × 4 = 0.5 × 16 = 8 units²

5 0
3 years ago
Read 2 more answers
An automobile manufacturer would like to know what proportion of its customers are not satisfied by the service provided by the
zheka24 [161]

Answer:

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Past studies suggest this proportion will be about 0.15

This means that p = 0.15

Find the sample size needed if the margin of error of the confidence interval is to be about 0.04

This is n when M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.15*0.85}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.15*0.85}

\sqrt{n} = \frac{1.96\sqrt{0.15*0.85}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.15*0.85}}{0.04})^{2}

n = 17.5

Rounding up

The sample size needed if the margin of error of the confidence interval is to be about 0.04 is 18.

8 0
3 years ago
Which transformation was applied to figure A to form figure B
Serga [27]

Answer:

The correct answer is A.


Hope this helped!



3 0
3 years ago
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