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Phoenix [80]
3 years ago
14

Language arts test is worth 100 points there is a total of 26 question There are spelling words question that I wasn't points ea

ch in vocabulary words question worth five points each how much of each type of question are there
Mathematics
1 answer:
Len [333]3 years ago
3 0

Answer: There are 10 two points and 16 five points questions.

Step-by-step explanation:

This is the detailed question:

A language arts test is worth 100 points. There are a total of 26 questions. There are spelling word questions that are worth 2 points each and vocabulary word questions worth 5 points each. How many of each type of question is there?

Let y = the number of 2 points questions

Let z = the number of 5 points questions

y + z = 26 ......... i

2y + 5z = 100 ........ ii

Multiply equation i by 2

Multiply equation ii by 1

2y + 2z = 52 ......... iii

2y + 5z = 100 ....... iv

Subtract iv from iii

-3z = -48

z = 48/3

z = 16

Since y + z = 26

y = 26 - 16

y = 10

y = 10 two points questions

z = 16 five points questions

There are 10 two points and 16 five points questions.

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6. Find the HCF of : (a) 21xy³ and 24x²y² (b) 18ab and 36abc <br>(c) 4p³q²r , -12pr² , 16p²q²r²r²​
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Step-by-step explanation:

<h2><u>➤ </u><u>Solution :-</u></h2><h2>a)</h2>

Given monomials are 21 xy³ and 24x²y²

21 xy³ = 3×7×x×y×y×y

24x²y² = 3×8×x×x×y×y

HCF of 21xy³ and 24x²y²

=> 3×x×y×y

=> 3xy²

HCF of 21xy³ and 24x²y² = 3xy²

<h2>b)</h2>

Given monomials are 18 ab and 36abc

18 ab = 18×a×b

36abc = 2×18×a×b×c

HCF of 18 ab and 36abc

=> 18×a×b

=> 18ab

HCF of 18 ab and 36abc = 18ab

<h2>c)</h2>

Given monomials are 4p³q²r , -12pqr² and 16p²q²r²

4p³q²r = 4×p×p×p×q×q×r

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16p²q²r² = 4×4×p×p×q×q×r×r

HCF of 4p³q²r , -12pqr² and 16p²q²r²

=> 4×p×q×r

=> 4pqr

HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr

<h2><u>Used Concept :-</u></h2>

→ The HCF of two or more numbers is the highest Common factor

→ The product of least common factors is the HCF of the numbers

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