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GarryVolchara [31]
3 years ago
14

Carlos bikes 2 1/2 miles in 1/4 hours. At that rate, how many miles would he bike in 1 hour?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
6 0

Answer:

10

Step-by-step explanation:

since it’s 1/4 1 out of the four is 2.5 so just multiply by four

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which of the following must be true for an expression to be a difference of two squares a.all variables are raised to an even po
Andrej [43]

Answer:

A.all variables are raised to an even power.

B. there are only two terms.

Step-by-step explanation:

An example of an expression that is a difference of two squares is:

= a² - b²

In this case;

Where both terms have an even power and there are only two terms.

5 0
3 years ago
Which fraction is equal to 1hole and 2/5?<br> a.3/5<br> b.75<br> c.57<br> d.73
zimovet [89]

Answer:

7/5

Step-by-step explanation:

This would be equal to 5/5 (the 1 hole) and 2/5

3 0
3 years ago
Read 2 more answers
Bob sees a very tall white pine tree. He estimates that the angle of elevation from him to the top of the tree is 77°
vlabodo [156]

Answer:

  86.63 ft

Step-by-step explanation:

The tangent relation applies.

  Tan = Opposite/Adjacent

  tan(77°) = (tree height)/(20 ft)

  tree height = (20 ft)·tan(77°) ≈ 86.63 ft

_____

<em>Additional comment</em>

It is somewhat problematic for Bob to see the top of a white pine tree at that angle of elevation. His view would likely be obscured by the branches of the tree.

8 0
2 years ago
What is the answer to this math problem: -6y+19=1+5+7y
lozanna [386]

Answer:

1

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
If θ is an angle in standard position and its terminal side passes through the point (-5,-6), find the exact value of
Mariana [72]

Answer:

\sec \theta = -\frac{\sqrt{61}}{5}

Step-by-step explanation:

The secant can be found by the following trigonometric relation:

\sec \theta = \frac{1}{\cos \theta}

\sec \theta = \frac{1}{\frac{x}{r} }

\sec \theta = \frac{r}{x}

\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}

\sec \theta = \frac{\sqrt{(-5)^{2}+(-6)^{2}}}{(-5)}

\sec \theta = -\frac{\sqrt{61}}{5}

6 0
3 years ago
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