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timofeeve [1]
3 years ago
7

6. Find the HCF of : (a) 21xy³ and 24x²y² (b) 18ab and 36abc (c) 4p³q²r , -12pr² , 16p²q²r²r²​

Mathematics
2 answers:
Fed [463]3 years ago
4 0
(a) 3xy^2(7y + 8x)
(b) 18ab(1 + 2c)
(c) 4pr(p^3q^2r - 3r + 4pq^2r)
Simora [160]3 years ago
3 0

Step-by-step explanation:

<h2><u>➤ </u><u>Solution :-</u></h2><h2>a)</h2>

Given monomials are 21 xy³ and 24x²y²

21 xy³ = 3×7×x×y×y×y

24x²y² = 3×8×x×x×y×y

HCF of 21xy³ and 24x²y²

=> 3×x×y×y

=> 3xy²

HCF of 21xy³ and 24x²y² = 3xy²

<h2>b)</h2>

Given monomials are 18 ab and 36abc

18 ab = 18×a×b

36abc = 2×18×a×b×c

HCF of 18 ab and 36abc

=> 18×a×b

=> 18ab

HCF of 18 ab and 36abc = 18ab

<h2>c)</h2>

Given monomials are 4p³q²r , -12pqr² and 16p²q²r²

4p³q²r = 4×p×p×p×q×q×r

-12pqr² = -3×4×p×q×r×r

16p²q²r² = 4×4×p×p×q×q×r×r

HCF of 4p³q²r , -12pqr² and 16p²q²r²

=> 4×p×q×r

=> 4pqr

HCF of 4p³q²r , -12pqr² and 16p²q²r² = 4pqr

<h2><u>Used Concept :-</u></h2>

→ The HCF of two or more numbers is the highest Common factor

→ The product of least common factors is the HCF of the numbers

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List the next four multiples of fraction 7/12
Sidana [21]
<h2>Hello!</h2>

The answer is:

\frac{14}{12}=\frac{7}{12}*2\\\\\\\frac{21}{12}=\frac{7}{12}*3\\\\\\\\\frac{28}{12}=\frac{7}{12}*4\\\\\\\\\frac{35}{12}=\frac{7}{12}*5

<h2>Why?</h2>

A multiple of a number is the repeated sum of itself, for example:

Multiple of the number 1 are: 1, 2, 3, 4, 5 and so...

Multiple of the number 3 are: 3, 6, 9, 12, 15 and so...

From the example we have:

Multiple of the number 3 are: Itself, (3+3), (3+3+3), (3+3+3+3), (3+3+3+3+3) and so...

So,

Multiple of \frac{7}{12} are:

\frac{14}{12}=\frac{7}{12}*2=\frac{7}{12}+\frac{7}{12}\\\\\\\frac{21}{12}=\frac{7}{12}*3=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{28}{12}=\frac{7}{12}*4=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}\\\\\\\\\frac{35}{12}=\frac{7}{12}*5=\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}+\frac{7}{12}

Have a nice day!

6 0
4 years ago
Help me out please???
xenn [34]

Answer:

(x,y) => (x+3, y+4)

Step-by-step explanation:

Given a triangle DEF, D(4,2), E(3,3), F(2,1).

Centroid of the area (and the vertices) equals the mean of the coordinates, namely ( (4+3+2)/3, (2+3+1)/3 ) = (3,2)

To translate (3,2) to (6,6), we need the rule

(x,y) => x+(6-3), y+(6-2), or

(x,y) => (x+3, y+4)

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Answer:

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x^2-3x-4=0

x^2-4x+x-4=0

x(x-4)+1(x-4)=0

(x+1)(x-4)=0

x=-1,4

x- intercepts in the point (-1,0) and (4,0)

Step-by-step explanation:

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