Answer:
Change in area=24
-48
Step-by-step explanation:
Let s will be the side of square and r will be the radius of circle.
Then two given conditions are
1)dr/dt=2 m/s
2)ds/dt=1 m/s
Area enclosed=(Area of square)-(Area of circle)
Area of square=
Area of circle=
Area enclosed=
dA/dt=2r(dr/dt)-2s(ds/dt)
At s=24,and r=6
dA/dt=2()(6)(2)-2(24)(1)
Change in area=24-48
-2=-x+x square-4
firstly regroup the equation
x square-2x+x-2=0
x square-x-2=0
multiply the first term by the last term.(I.e x square multiply by -2=-2x square)
product of factor = -2x 1
sum of factor= -2x+1(x)= -1
x square -2x+x-2=0
open the bracket:
x(x-2)+1(x-2)=0
x=1 or x=-2
Therefore; x=-1 or x=2
The terms in the sum are given by the sequence
We have
for all 
, and the series 
clearly diverges, so 
must also diverge.
Area of a triangle=1/2(base x height)
Area=72, Base=8, Height=2x-3
Plug it in.
72=1/2(8 x (2x-3))
72=1/2(16x-24)
72=8x-12
84=8x
x=10.5
30 dolls.
You can get this by multiplying the number in 20% by 5, which would get you to 100% and 30.
