<span> (8^ -2)(4^4)(16^ -1)
</span>
<span>a^-x=(1/a^x)
</span>
<span> (4^4)/((8^2)(16))
"NOTE" </span><span>16^1=16
</span>
<span>4^4=256
8^2=64
256/((64)(16))=1/4
</span>
<span>convert 1/4 to a power of two
</span>
<span>(4) is 2
1/4=1/(2^2)
</span>
<span>1^2=1
(1/2)^2=(1/4)
</span>
<span>1/2 to the power of 2 is the answer
It would look like this
1/2²</span>
3 (three) times x (a number) - (minus) 7 (seven)
Three times a number minus seven
You could also say seven less than the product of a number and three.
Answer:
The rocket will reach its highest point about 2.04 seconds.
Step-by-step explanation:
The function:

Models the relationship between the height of the rocket and the time after launch t in seconds.
Since this is a quadratic function, the rocket will reach its highest point at its vertex. The vertex of a quadratic is given by:

In this case, a = -4.9, b = 20, and c = 0. Thus:

The rocket reaches its maximum height after 10/4.9 or about 2.04 seconds.
Further Notes:
Then the maximum height of the rocket will be f(10/4.9):

Answer:
1.4 is a rational number because it has a terminal decimals. it is the same as 14/10