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DiKsa [7]
2 years ago
10

The box plot was created by using which pieces of data? A) an upper quartile of 56 and a median of 50 B) a lower quartile of 56

and a median of 50 C) a median of 56 and a lower quartile of 50 D) a median of 56 and an upper quartile of 50

Mathematics
1 answer:
Jlenok [28]2 years ago
6 0

Answer:

A) an upper quartile of 56 and a median of 50

Step-by-step explanation:

Hello!

The lower and upper ends "box" from the box and whiskers plot is determined by the first (Q₁) and third (Q₃) quartiles of the data set and the line inside the box marks the median or second quartile of the sample (Q₂)

The length of the whiskers of the diagram is determined by the minimum value (left whisker) and the maximum value (right whisker)

If you observe the graphic:

Q₁= 42

Q₂= 50 (Median)

Q₃= 56

Min= 38

Max= 66

The box is delimited by a lower quartile of 42 and an upper quartile of 56, with a median 50, the least observation is 38 and the highest observation is 66.

The correct choice is A.

I hope this helps!

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MaRussiya [10]

Answer:

x = 2.25 or any number greater

Step-by-step explanation:

5x3 > 4 + 8 + x

Make them equal to each other to get x

5x3 = 4 + 8 + x

(5x)(3) = 12 + x

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4x = 9

\frac{4x}{4} = \frac{9}{4}

x = 2.25

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Step-by-step explanation:

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3 years ago
The amount of protein that an individual must consume is different for every person. There are solid theoretical ideas that sugg
amid [387]

Answer:

The proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is 0.239, that is, 239 persons for every 1000, or simply 23.9% of them.

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

Step-by-step explanation:

From the question, we have the following information:

  • The distribution for protein requirement is <em>normally distributed</em>.
  • The population mean for protein requirement for adults is \\ \mu= 0.65 gP*kg^{-1}*d^{-1}
  • The population standard deviation is \\ \sigma =0.07 gP*kg^{-1}*d^{-1}

We have here that protein requirements in adults is normally distributed with defined parameters. The question is about <em>the proportion</em> <em>of the population</em> that has a requirement less than \\ x = 0.60 gP*kg^{-1}*d^{-1}.

For answering this, we need to calculate a <em>z-score</em> to obtain the probability of the value <em>x </em>in this distribution using a <em>standard normal table</em> available on the Internet or on any statistics book.

<h3>z-score</h3>

A z-score is expressed as

\\ z = \frac{x - \mu}{\sigma}

For the given parameters, we have:

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = \frac{0.60 - 0.65}{0.07}

\\ z = -0.7142857

<h3>Determining the probability</h3>

With this value for <em>z</em> at hand, we need to consult a standard normal table to determine what the probability of this value is.

The value for z = -0.7142857 is telling us that the requirement for protein is below the population mean (negative sign indicates this). However, most standard normal tables give a probability that a statistic is less than z and for values greater than the mean (in other words, positive values). To overcome this, we need to take the complement of the probability given for z-score z = 0.7142857, that is, subtract from 1 this probability, which is possible because the normal distribution is <em>symmetrical</em>.

Tables have values for <em>z</em> with two decimal places, then, for z = 0.7142857, we need to rewrite it as z = 0.71. For this value, the <em>standard normal table</em> gives a value of P(z<0.71) = 0.76115.

Therefore, the cumulative probability for values less than x = 0.60 which corresponds to a z-score = -0.7142857 is approximately:

\\ P(x

\\ P(x (rounding to three decimal places)

That is, the proportion of the population that have a protein requirement less than 0.60 g P • kg-1 • d-1 is

\\ 0.239 =\frac{239}{1000}\;or\;23.9\%

See the graph below. The shaded area is the region that represents the proportion asked in the question.

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balu736 [363]

Answer:

see below

Step-by-step explanation:

1.

1, H - 2, H - 3, H - 4, H - 5, H

1, T - 2, T - 3, T - 4, T - 5, T

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2,H is one out of 10 possible outcomes, so the probability is 1/10

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