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3 years ago

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An arena is hosting a concert. At the most, the arena can hold 8,500 people. If tickets have already been sold to 6,900 people,

what is the highest number of tickets that can still be sold?

1 answer:

ElenaW [278]3 years ago

8 0

Answer:

Subtract 6,900 from 8,500 to get the highest number of tickets that can still be sold which is 1,600.

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dybincka [34]

I suppose you mean

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To see this, recalling the series for $\sin x$ , we know

$\sin(x^2)=\displaystyle\sum_{n=0}^\infty(-1)^{n-1}\frac{x^{4n+2}}{(2n+1)!}$

Multiplying by $-2x$ gives

$-x\sin(x^2)=\displaystyle2x\sum_{n=0}^\infty(-1)^n\frac{x^{4n}}{(2n+1)!}$

and from here,

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Lisa [10]

Comment
There are 12 months in a year. He plans on visiting 8 times each month.

Step One
Find the number of visits per year.

<em>Givens</em>
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Visits = # visits / month * number of months
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Step Two
<em>Calculate the cost / visit</em>
Total Cost = 414 visits.
Total Visits = 96

Cost / Visit = Total Cost / Total visits.
Cost / Visit = 414 / 96
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