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kirill115 [55]
3 years ago
12

An arena is hosting a concert. At the most, the arena can hold 8,500 people. If tickets have already been sold to 6,900 people,

what is the highest number of tickets that can still be sold?
Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

Subtract 6,900 from 8,500 to get the highest number of tickets that can still be sold which is 1,600.

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olga2289 [7]

\text{The sum of } 1\frac{7}{10}  \text{ and } 3\frac{3}{5} \text{ is } 5\frac{3}{10}

<em><u>Solution:</u></em>

Given that we have to find the sum of 1\frac{7}{10} \text{ and } 3\frac{3}{5}

<em><u>Let us first convert the mixed fractions to improper fractions</u></em>

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Make the denominators same

1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{18 \times 2}{5 \times 2}\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17}{10} + \frac{36}{10}\\\\\text{Add the fractions since the denominator is same }\\\\1\frac{7}{10} + 3\frac{3}{5} = \frac{17+36}{10} = \frac{53}{10}

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