1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry_Shevchenko [17]
3 years ago
10

‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️I need help ASAP 30 points and brainliest to correct answer and most helpful. Please elaborate and explain y

our answer. The chart for number 3 is attached above
In this experiment, you will be using two coins as a simulation for a real-world compound event.



1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.



What is the theoretical probability that the family has two dogs or two cats?


2. Describe how to use two coins to simulate which two pets the family has.


3. Flip both coins 50 times and record your data in a table like the one below. ( the chart is the picture that I attached)



Result Frequency


Heads, Heads


Heads, Tails


Tails, Heads


Tails, Tails


Total 50


Based on your data, what is the experimental probability that the family has two dogs or two cats?


4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?


5. How could you change the simulation to generate data for three pets?

Mathematics
2 answers:
Strike441 [17]3 years ago
5 0
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

What is the theoretical probability that the family has two dogs or two cats?

25% chance

</span><span>2. Describe how to use two coins to simulate which two pets the family has.
</span>
You could use the coins to simulate which pet the family has by flipping them and having head be dog and tails be cat (or vice-versa). 

<span>3. Flip both coins 50 times and record your data in a table like the one below.

</span><span>Based on your data, what is the experimental probability that the family has two dogs or two cats?
</span>
Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

<span>4. If the family has three pets, what is the theoretical probability that they have three dogs or three cats?

1/8 chance (accidentally messed up there) or 12.5%

</span><span>5. How could you change the simulation to generate data for three pets?
</span><span>
To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

</span>
Tems11 [23]3 years ago
3 0

I just wrote this answer so the other guy could get brainliest! He got me 100% too!!!

You might be interested in
The time between arrivals of customers at the drive-up window of a bank follows an exponential probability distribution with a m
castortr0y [4]

Answer:

a) 50.34% probability that the arrival time between customers will be 7 minutes or less.

b) 24.42% probability that the arrival time between customers will be between 3 and 7 minutes

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

Mean of 10 minutes:

This means that m = 10, \mu = \frac{1}{10} = 0.1

A. What is the probability that the arrival time between customers will be 7 minutes or less?

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

50.34% probability that the arrival time between customers will be 7 minutes or less.

B. What is the probability that the arrival time between customers will be between 3 and 7 minutes?

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3)

P(X \leq x) = 1 - e^{-\mu x}

P(X \leq 7) = 1 - e^{-0.1*7} = 0.5034

P(X \leq 3) = 1 - e^{-0.1*3} = 0.2592

P(3 \leq X \leq 7) = P(X \leq 7) - P(X \leq 3) = 0.5034 - 0.2592 = 0.2442

24.42% probability that the arrival time between customers will be between 3 and 7 minutes

3 0
3 years ago
Lanas family is planning a rectangular garden. They make a scale diagram of the garden using a scale of 1 in. to 0.5 meter. If t
d1i1m1o1n [39]
The perimeter is everything added up, since its not a square then you add not multiply. 24+24=48 and 16+16=32, add 32 and 48 and get 80.                                                                                                                                                                                                                                                  Answer:80
8 0
3 years ago
5|2x - 3| + 4 = 9<br> How do you solve this
agasfer [191]

Answer:

x = 2, or x = -1

Step-by-step explanation:

If 2x - 3 is inside the parenthesis (), then the value of x is 2.

If 2x - 3 is inside the absolute value sign, then the value of x will probably be -1.

<u>Solution 1</u>

(10x-15) + 4 = 9

10x -11 = 9

10x = 20    -> x = 2

<u>Solution 2</u> (Not 100% sure)

|10x -15| +4 = 9

10x + 15 +4 = 9

10x + 19 = 9

10x = -10      -> x = -1

Please correct me if I'm wrong.

<u />

3 0
3 years ago
*WILL GIVE BRAINLIEST*
Nookie1986 [14]
Basically each side of the triangle represents a square on each which then makes the hypotenuse the largest square. Now, the area of a square is formulated by (1 side)² . Pythagorean theorem says that the area of the largest square is the sum of the 2 smaller square which is why the formula is a² + b² = c².
7 0
4 years ago
Graph the line y=-5/3x-1
Pepsi [2]

Answer:

Put a dot on -1. Go down 5 and then 3 to the right. You will have two points which is enough to make a line. Grab a ruler and connect both of them. You have the line y=-5/3x-1 graphed


Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
Other questions:
  • Add parentheses to make this equation true 4+8-2×3-7=15
    10·2 answers
  • 6x+7x=4x+4y complete the missing value in the solution to the equation (?,-4)
    13·1 answer
  • On the first day of the fiscal year, a company issues $65,000, 6%, five-year installment
    10·1 answer
  • Model and solve 4÷2/3=
    7·2 answers
  • Helpp degrees, minutes, and seconds​
    11·1 answer
  • Four different stores posted ads on special 15-oz cans of baked beans -8 for $6 = 75 cents per can -10 for $10 = $1 per can -2 f
    8·2 answers
  • PLEASE HELP I WILL GIVE BRAINLIEST!!!
    14·2 answers
  • Paul is adding mulch along the edge of his driveway. He orders 7 bags of mulch for $392. How much would it cost if Paul orders 9
    10·2 answers
  • Four more than the price p
    15·1 answer
  • In the statement
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!