STEP
1
:
y
Simplify —
3
Equation at the end of step
1
:
y
(((18•(x5))•(y3))+((6•(x2))•(y4)))+((((24•(x6))•—)•x)•y)
3
STEP
2
:
Equation at the end of step
2
:
y
(((18•(x5))•(y3))+((6•(x2))•(y4)))+((((23•3x6)•—)•x)•y)
3
STEP
3
:
Canceling Out:
3.1 Canceling out 3 as it appears on both sides of the fraction line
Equation at the end of step
3
:
(((18•(x5))•(y3))+((6•(x2))•(y4)))+((8x6y•x)•y)
STEP
4
:
Equation at the end of step
4
:
(((18•(x5))•(y3))+((2•3x2)•y4))+8x7y2
STEP
5
:
Equation at the end of step
5
:
(((2•32x5) • y3) + (2•3x2y4)) + 8x7y2
STEP
6
:
STEP
7
:
Pulling out like terms
7.1 Pull out like factors :
8x7y2 + 18x5y3 + 6x2y4 = 2x2y2 • (4x5 + 9x3y + 3y2)
Trying to factor a multi variable polynomial :
7.2 Factoring 4x5 + 9x3y + 3y2
Try to factor this multi-variable trinomial using trial and error
Factorization fails
Final result :
2x2y2 • (4x5 + 9x3y + 3y2)
Answer:
It's B. 42 divided by 6 = 7
Step-by-step explanation:
A quotient is the result you get when you divide, and only one of them is division.
Hope this helped lots and lots,
Sincerely, me
Answer:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.
So 292 - 240 = 52 read below or at eight grade level, and that 
80% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:

The upper limit of this interval is:

The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
1)
1 = 38
2 = 38
3 = 38
4 = 38
2)
1 = 32
2 = 90
3 = 58
4 = 32
Let me know if I'm wrong.
The equation is 1.2t=50.2 And the solution is 42