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qwelly [4]
3 years ago
5

Malcolm is downloading a file that is 50.4 Mb. his internet connection has a download speed of 1.2 mb per second. Let t represen

t the amount of time in seconds it will take to download the file.Write and solve a multiplication equation to find the time in seconds it will take Malcolm to download the file
Mathematics
1 answer:
VikaD [51]3 years ago
5 0
The equation is 1.2t=50.2 And the solution is 42
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Advertising expenses are a significant component of the cost of goods sold. Listed below is a frequency distribution showing the
Alexxandr [17]

Answer:

Step-by-step explanation:

The table can be computed as:

Advertising Expenses ($ million)     Number of companies

25 up to 35                                                    4

35 up to 45                                                    19

45 up to 55                                                    27

55 up to 65                                                    16

65 up to 75                                                     9

TOTAL                                                            75

Let's find the probabilities first:

P(25 - 35) = P \Big(\dfrac{25-50.93}{10.80}

For 35 up to 45

P(35 - 45) = P \Big(\dfrac{35-50.93}{10.80}

For 45 up to 55

P(45 - 55) = P \Big(\dfrac{45-50.93}{10.80}

For 55 up to 65

P(55 - 65) = P \Big(\dfrac{55-50.93}{10.80}

For 65 up to 75

P(65 - 75) = P \Big(\dfrac{65-50.93}{10.80}

Chi-Square Table can be computed as follows:

Expense   No of   Probabilities(P)  Expe                (O-E)^2   \dfrac{(O-E)^2}{E}

             compa                                 cted E (n*p)

             nies (O)  

25-35           4      0.0612    75*0.0612 = 4.59        0.3481       0.0758

35-45           19     0.2218   75*0.2218 = 16.635     5.5932       0.3362

45-55           27     0.3568   75*0.3568 = 26.76     0.0576      0.021

55-65           16      0.2552   75*0.2552 = 19.14      9.8596      0.5151

65-75           9      0.0839     75*0.0839 = 6.2925   7.331         1.1650

                                                                                           \sum \dfrac{(O-E)^2}{E}= 2.0492                                                                                                      

Using the Chi-square formula:

X^2 = \dfrac{(O-E)^2}{E} \\ \\ Chi-square  \ X^2 = 2.0942

Null hypothesis:

H_o: \text{The population of advertising expenses follows a normal distribution}

Alternative hypothesis:  

H_a: \text{The population of advertising expenses does not follows a normal distribution}

Assume that:

\alpha = 0.02

degree of freedom:

= n-1

= 5 -1

= 4

Critical value from X^2 = 11.667

Decision rule: To reject H_o  \  if \  X^2  test statistics is greater than X^2 tabulated.

Conclusion: Since X^2 = 2.0942 is less than critical value 11.667. Then we fail to reject H_o

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What is the measure of the missing angle in the triangle below?
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Answer:

<em>41 degrees</em>

Step-by-step explanation:

<em>According to Angle Sum Property, the sum of the internal angles of a triangle is equal to 180 degrees.</em>

<em>Therefore,</em>

<em>52 + 87 + ? = 180</em>

<em>139 + ? = 180</em>

<em>? = 180 - 139</em>

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Answer:

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vredina [299]

Answer:

A= $0.60

B= $5.62

Step-by-step explanation:

A: If you do 1.5*0.10, the product will be 0.15. If you do 1.5*0.50, the product would be 0.75. So, 0.75-0.15 is 0.6.

B: 2.5*0.50 is 1.25 and 1.25*0.10 is 0.125. So, if you add the products together, you would get 1.375 but because it's money, you have to round it to $1.38 and $7-$1.38 is $5.62.

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