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Strike441 [17]
3 years ago
11

Solve for x. A.40 B.55 C.20 D.35

Mathematics
1 answer:
fomenos3 years ago
3 0

Answer:

20

Step-by-step explanation:

The angles are vertical angles which means they are equal

60 = 2x+20

Subtract 20 from each side

60-20 = 2x+20-20

40 =2x

Divide by 2

40/2 = 2x/2

20 =x

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Find the difference of functions s and r shown below. r(x) = -x² + 3x s(x) = 2x + 1 ( s-r)(x)=​
drek231 [11]

Answer:

Part 1)

(s-r)(x)=(2x+1)-(-x^2+3x)

Part 2)

(s-r)(x)=x^2-x+1

Step-by-step explanation:

Part 1)

So we have the two functions:

r(x)=-x^2+3x\text{ and } s(x)=2x+1

And we want to find:

(s-r)(x)

This is the same as:

=s(x)-r(x)

Substitute:

=(2x+1)-(-x^2+3x)

So, our answer for Part A is:

=(2x+1)-(-x^2+3x)

Part 2)

Let's find our difference.

Distribute the -1:

=(2x+1)+(x^2-3x)

Combine like terms:

=(x^2)+(2x-3x)+(1)

Add:

=x^2-x+1

And we're done!

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I need help with this!
lisabon 2012 [21]

Answer:

angle j = 90

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angle L = 61

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2/3(3x-5)=3 Solve for x
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2/3 (3x-5)=3

x=19/6

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