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USPshnik [31]
2 years ago
14

The diameter of a cylindrical water tank is 12 ft, and its height is 14 ft. What is the volume of the tank?

Mathematics
1 answer:
r-ruslan [8.4K]2 years ago
6 0

balalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalalala

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I need this answered plz!!!!!!!!!!!!!!!!!!!
Fynjy0 [20]

Answer:

Red: Left side equation

Blue: Right side equation

2x+7=2(x-1)

2x+7=2x-2

2x-2x=-2-7

0x=-9= 0 No solution

Step-by-step explanation:

Use Desmos graphing calculator if u need help with graphs

6 0
3 years ago
Nvm the questions change if anyone wants these points then your free to have em
sasho [114]

Answer:

ok thanks :)

Step-by-step explanation:

4 0
3 years ago
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Make L the subject of the formula T=2π√L\G​
Trava [24]

Answer:

T^2=4π^2*L/G

L=(T^2*G)/4π^2

Step-by-step explanation:

hope this helps

4 0
3 years ago
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How do you solve this?
oksian1 [2.3K]

Answer:

X=73/7

Step-by-step explanation:

7 0
3 years ago
4. Gloria the grasshopper is working on her hops.
aivan3 [116]

The path that Gloria follows when she jumped is a path of parabola.

The equation of the parabola  that describes the path of her jump is \mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}

The given parameters are:

\mathbf{Height = 20}

\mathbf{Length = 28}

<em>Assume she starts from the origin (0,0)</em>

The midpoint would be:

\mathbf{Mid = \frac 12 \times Length}

\mathbf{Mid = \frac 12 \times 28}

\mathbf{Mid = 14}

So, the vertex of the parabola is:

\mathbf{Vertex = (Mid,Height)}

Express properly as:

\mathbf{(h,k) = (14,20)}

A point on the graph would be:

\mathbf{(x,y) = (28,0)}

The equation of a parabola is calculated using:

\mathbf{y = a(x - h)^2 + k}

Substitute \mathbf{(h,k) = (14,20)} in \mathbf{y = a(x - h)^2 + k}

\mathbf{y = a(x - 14)^2 + 20}

Substitute \mathbf{(x,y) = (28,0)} in \mathbf{y = a(x - 14)^2 + 20}

\mathbf{0 = a(28 - 14)^2 + 20}

\mathbf{0 = a(14)^2 + 20}

Collect like terms

\mathbf{a(14)^2 =- 20}

Solve for a

\mathbf{a =- \frac{20}{14^2}}

\mathbf{a =- \frac{20}{196}}

Simplify

\mathbf{a =- \frac{5}{49}}

Substitute \mathbf{a =- \frac{5}{49}} in \mathbf{y = a(x - 14)^2 + 20}

\mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}

Hence, the equation of the parabola  that describes the path of her jump is \mathbf{y = -\frac{5}{49}(x - 14)^2 + 20}

See attachment for the graph

Read more about equations of parabola at:

brainly.com/question/4074088

7 0
3 years ago
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