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jeyben [28]
3 years ago
12

Please, please , please help.​

Mathematics
2 answers:
Phantasy [73]3 years ago
5 0

Answer:

top 3,6,9

Bottom 60,120 ,180

Step-by-step explanation:

topjm [15]3 years ago
3 0

Answer:

60,120,180

3,6,9

Step-by-step explanation:

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Graph the function f.​
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5. Angie is mixing together yellow paint and blue paint to make 2 shades of green paint. She fills −4 of can A with yellow paint
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3 years ago
At the arcade, Jamal had 6 tickets that he had saved from last time he went. This time he played the same game 7 times and earne
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3 years ago
At a local University, it is reported that 81% of students own a wireless device. If 5 students are selected at random, what is
Sphinxa [80]

Answer:

34.87% probability that all 5 have a wireless device

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they own a wireless device, or they do not. The probability of a student owning a wireless device is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

81% of students own a wireless device.

This means that p = 0.81

If 5 students are selected at random, what is the probability that all 5 have a wireless device?

This is P(X = 5) when n = 5. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{5,5}.(0.81)^{5}.(0.19)^{0} = 0.3487

34.87% probability that all 5 have a wireless device

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3 years ago
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wlad13 [49]

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3 years ago
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