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3 years ago

How do I solve this problem(3x-4y)-(6x-28y)

Mathematics

2 answers:

Tema [17]3 years ago

5 0

Answer:

3x-4y-6x+28y

-3x-6x-4y+28y

-9x+24y

Step-by-step explanation:

aliya0001 [1]3 years ago

5 0

Answer:

Step-by-step explanation:

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Please help me with this I don't really understand it

tino4ka555 [31]

Answer:

Step-by-step explanation:

-39

6 0

3 years ago

Someone please help me!!!

djyliett [7]

Answer:

A 34

Step-by-step explanation:

The measure of the angle is 1/2 the measure of the larger arc - 1/2 the measure of the smaller arc

VXY = 1/2( VZ - WY)

= 1/2( 93-25)

=1/2 (68)

=34

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4 years ago

8x2 − 5 + 7x4 − 9x − x5

Veseljchak [2.6K]

Answer:

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

Step-by-step explanation:

Factor out comon Term -1

$=-\left(x^5-7x^4-8x^2+9x+5\right)$

Factor $x^5-7x^4-8x^2+9x+5:\quad \left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

$x^5-7x^4-8x^2+9x+5$

Use the rational root theorem

$a_0=5,\:\quad a_n=1$

The dividers of $a_{0}$ : 1, 5, The dividers of $a_n$ : 1

Therefore, check the following rational numbers: ± $\frac{1,\:5}{1}$

$\frac{1}{1}$ is a root of the expression, so factor out $x-1$

$=\left(x-1\right)\frac{x^5-7x^4-8x^2+9x+5}{x-1}$

$\frac{x^5-7x^4-8x^2+9x+5}{x-1}=x^4-6x^3-6x^2-14x-5$

$=x^4-6x^3-6x^2-14x-5$

$=-\left(x-1\right)\left(x^4-6x^3-6x^2-14x-5\right)$

8 0

3 years ago

What is the correlation coefficient for the data shown in the table?

Leviafan [203]

we know that

The correlation coefficient is a number between $-1$ and $+1$ that represent the linear dependence of two variables or sets of data

Using the function CORREL in a excel tool, calculate the correlation coefficient (r)

see the attached table

the correlation coefficient for the data in the table is equal to $1$

therefore

the answer is

$r=1$

7 0

3 years ago

Read 2 more answers

What is the answer to -4 + c = -11

wlad13 [49]

Answer: c = -7

Step-by-step explanation:

-4 + c = -11

c = -7

5 0

3 years ago