Answer:
How are we supposed to know .???
we can only see half of the problem
Step-by-step explanation:
x + y = 3.36 --> the boys are splitting $3.36
x = 3y - .12 --> one boy received $.12 less than 3 times as much as the other
--> substitute the second equation for the x in the first equation
(3y - .12) + y = 3.36 --> combine like terms
4y - .12 = 3.36 --> add .12 to both sides of the equation
4y = 3.48 --> divide both sides by 4
y = .87
the other boy gets $0.87
substitute into x = 3y - 12
x = 3(.87) - .12
x = 2.61 - .12
x = 2.49
the first boy gets $2.49
Answer:
With all the lines, I may be wrong. But I'm confident that line B has a slope of 2.
This is because it rises up 2 up the y axis for every one unit on the x axis.
Answer:
Step-by-step explanation:
c
We have to assume that the speed before being stuck was sufficient to get to the destination on time had there been no delay. Call that speed "s" in km/h.
Since 200 km is "halfway", the total distance must be 400 km.
time = distance / speed
total time = (time for first half) + (delay) + (time for second half)
400/s = 200/s + 1 + 200/(s+10) . . . .times are in hours, distances in km
200/s = 1 + 200/(s+10) . . . . . . . . . . subtract 200/s
200(s+10) = s(s+10) +200s . . . . . . .multiply by s(s+10)
0 = s² +10s - 2000 . . . . . . . . . . . . . .subtract the left side
(s+50)(s-40) = 0
Solutions are s = -50, s = 40
The speed of the bus before the traffic holdup was 40 km/h.
