All categories

2 years ago

Which of the following structures are NOT found in the cytoplasm?

Biology

2 answers:

ElenaW [278]2 years ago

8 0

Answer:

MRCORRECT has answered the question

Explanation:

D)chloroplast

aleksley [76]2 years ago

7 0

Answer:

Nucleus

Explanation:

You might be interested in

Question 32 ribosomes carry out dna-directed protein synthesis. carry out rna processing are not found in prokaryotes. of mitoch

Tom [10]

The answer is the Ribosomes of mitochondria and plastids are very similar in their structure and function to bacterial ribosomes.Mitochondria, chloroplasts, and bacteria are alike in size. Bacteria also have DNA and ribosomes alike to those of mitochondria and chloroplasts. Based on this and other proof, experts ponder host cells and bacteria shaped endosymbiotic relationships precedent, when separate host cells took in oxygen-using and photosynthetic bacteria but did not put an end to them.

6 0

3 years ago

Which of the following allows a plants vascular system to work as a transport system

rosijanka [135]

"A plants vascular system is made up of specialized cells that for straw-like tubes" is the one among the following that allows a plant's vascular system to work as a transport system. The correct option among all the options that are given in the question is the third option or option "C". I hope this helps.

5 0

2 years ago

Which of these sources add water to lakes? Select three correct answers.

Pepsi [2]

A.SURFACE RUNOFF FROM RAIN.

C.MELTING ICE

B.OCEAN CURRENTS ( I guess?)

[that's it]:)

6 0

2 years ago

When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red

Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

RR- red
ww - white
Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

From this cross the expected ratios are:

1/4 RR (red)
2/4 Rw (pink)
1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3>Chi square test</h3>

$X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}$

The observed frequencies were:

34 Red
76 Pink
40 White

Total 150

The expected frequencies for our null hypothesis are:

1/4 x 150 = 37.5 Red
2/4 x 150 = 75 Pink
1/4 x 150 = 37.5 white

$X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}$

$X^2=0.5067$

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0

3 years ago

A man riding his bike had a velocity of 5 meters per second north. After 10 seconds, his velocity increased to 9 meters per seco

VashaNatasha [74]

4 mps increase in 10 seconds = 2 mps increase in 5 seconds = .4meters/2sec

6 0

2 years ago

Read 2 more answers