I believe the answer could be a variable
Answer:
9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;
(x - 2)²/2² - (y + 3)²/3² = 1
Step-by-step explanation:
The standard form of a hyperbola is given as follows;
(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1
The given equation is presented as follows;
9·x² - 36·x = 4·y² + 24·y + 36
By completing the square, we get;
(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)
(3·x - 6)² - 36 = (2·y + 6)²
(3·x - 6)² - (2·y + 6)² = 36
(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1
(3·x - 6)²/6² - (2·y + 6)²/6² = 1
3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1
(x - 2)²/2² - (y + 3)²/3² = 1
The equation of the hyperbola is (x - 2)²/2² - (y + 3)²/3² = 1.
Domain refers to all of the x-values that satisfy the line, and the range refers to all of the y-values that satisfy the line.
Since t corresponds to the x-ordinates, then the domain becomes:
0 ≤ t ≤ 6
and the range becomes:
0 ≤ v ≤ 150
In short, the answer is (A)
Let
x--------> the larger integer
y-------> the smaller integer
we know that
x²+y²=394-----> equation 1
x=y+2-----> equation 2
substitute equation 2 in equation 1
[y+2]²+y²=394-----> y²+4y+4+y²=394
2y²+4y-390=0
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
y=13
x=y+2---> x=13+2---> x=15
the answer isthe numbers are 15 and 13