Answer: the box contained 9 square chocolates and 15 round chocolates.
Step-by-step explanation:
Let x represent the number of square chocolates contained in the box.
Let y represent the number of round chocolates contained in the box.
The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that
10x + 8y = 210- - - - - - - - - - -1
The number of round chocolates is 3 less than twice the number of square chocolates. It means that
y = 2x - 3
Substituting y = 2x - 3 into equation 1, it becomes
10x + 8(2x - 3) = 210
10x + 16x - 24 = 210
26x = 210 + 24
26x = 234
x = 234/26
x = 9
y = 2x - 3 = 2 × 9 - 3
y = 18 - 3
y = 15
Ths phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be D. the sum of three times a number and six divided by the difference of seven times the number and nine.
<h3>How to illustrate the algebra?</h3>
It should be noted that an algebra is simply used to show the relationship between variables.
Here, the phrase that represents the algebraic expression (3p + 6)/(7p - 9) will be the sum of three times a number and six divided by the difference of seven times the number and nine.
In conclusion, the correct option is D.
Learn more about algebra on:
brainly.com/question/723406
#SPJ1
Given:
The degree of polynomial = 9
Leading coefficient is negative.
To find:
The end behavior of the polynomial.
Solution:
Let the polynomial be P(x).
We have,
Degree of polynomial = 9, which is odd.
Leading coefficient is negative.
If the degree of a polynomial is odd and leading coefficient is negative, then
Therefore, the end behavior of the given polynomial is 
.
