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Licemer1 [7]
3 years ago
10

5c+4c+2 and 5c+2(2c+1)

Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

11 c12 cyfiddiddjkssjksajusaahogsyi of

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IrinaVladis [17]

Answer:

80cause there are 80 sides


3 0
2 years ago
Find the vertex of the parabola<br> y= x^2-2x-1<br> vertex (?,?)
SpyIntel [72]
y=ax^2+bx+c\\\\vertex:(x_v;\ y_v)\\\\x_v=\frac{-b}{2a}\ and\ y_v=f(x_v)


y=x^2-2x-1\\\\a=1;\ b=-2;\ c=-1\\\\x_v=\frac{-(-2)}{2\cdot1}=\frac{2}{2}=1\\\\y_v=1^2-2\cdot1-1=1-2-1=-2\\\\Answer:(1;-2)
5 0
3 years ago
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Can anyone tell me if these answers are right?
k0ka [10]

Answer:

Ummm. 1 & 3 look good double check 2

Step-by-step explanation:

HELPFUL?

8 0
3 years ago
Find the derivative of f(x) = 2x^2 - 4x +3
ivolga24 [154]

Explanation

2x^2-4x+3

When taking derivatives of polynomials, we primarily make use of the power rule.

Power rule.

\begin{gathered} f(x)=x^n \\ \text{then} \\ f^{\prime}(x)=nx^{n-1} \end{gathered}

also, the derivate of a sum is the sum of the derivates

hence

\begin{gathered} g(x)=f(x)+h(x)+\ldots z(x) \\ g^{\prime}(x)=f^{\prime}(x)+h^{\prime}(x)+\ldots.z^{\prime}(x) \end{gathered}

Step 1

apply:

\begin{gathered} f(x)=2x^2-4x+3 \\ f^{\prime}(x)=2\cdot2x^{2-1}-4(1)x^{1-1}+ \\ f^{\prime}(x)=4x^{}-4(1)x^0+3^0 \\ f^{\prime}(x)=4x^{}-4(1)(1) \\ f^{\prime}(x)=4z-4 \end{gathered}

therefore, the answer is

8 0
1 year ago
Write as a fraction in simplest form<br> .56 =
nirvana33 [79]

Answer:

14/25

Step-by-step explanation:

7 0
3 years ago
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