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Licemer1 [7]
3 years ago
10

5c+4c+2 and 5c+2(2c+1)

Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

11 c12 cyfiddiddjkssjksajusaahogsyi of

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What is the slope of the line containing (-2,5) and (4, -4)?
Musya8 [376]

Answer: slope is -3/2

Step-by-step explanation:

(-2,5) (4,-4)

Use the slope formula y2-y1/x2-x1

5-(-4)/-2-4 = -3/2

6 0
3 years ago
Read 2 more answers
A fish tank has the shape of a rectangular prism. It has a length of 2 1/4 meters, width of 7/8 meters, and a height of 1 1/2 me
bazaltina [42]

volume = L x W X H

2 1/4 x 7/8 x 1 1/2 = 2 61/64 cubic meters

1 cubic meter = 1000 liters

2 61/64 = 2.953125

2.953125 * 1000 = 2,953.125 liters ( Round answer as needed )



please mark brainliest

3 0
3 years ago
Read 2 more answers
* please explain work / show it thxsss!!**
serious [3.7K]

Answer:

All you need to do is to calculate the perimeter of the circle since you already had the diameter

Base on the picture, the perimeter should be:

C = d * π = 64 * 3.14 = 200.96 (m)

8 0
3 years ago
20 points and brainliest <br> I’m in quiz in need it asap <br> Number 4
iren [92.7K]

Answer and step-by-step explanation:

The polar form of a complex number a+ib is the number re^{i\theta} where r = \sqrt{a^2+b^2} is called the modulus and \theta = tan^-^1 (\frac ba) is called the argument. You can switch back and forth between the two forms by either remembering the definitions or by graphing the number on Gauss plane. The advantage of using polar form is that when you multiply, divide or raise complex numbers in polar form you just multiply modules and add arguments.

(a) let's first calculate moduli and arguments

r_1 = \sqrt{(-2\sqrt3)^2+2^2}=\sqrt{12+4} = 4\\ \theta_1 = tan^-^1(\frac{2}{-2\sqrt3}) =-\pi/6\\r_2=\sqrt{1^2+1^2}=\sqrt2\\ \theta_2 = tan^-^1(\frac 11)= \pi/4

now we can write the two numbers as

z_1=4e^{-i\frac \pi6}; z_2=e^{i\frac\pi4}

(b) As noted above, the argument of the product is the sum of the arguments of the two numbers:

Arg(z_1\cdot z_2) = Arg(z_1)+Arg(z_2) = -\frac \pi6 + \frac \pi4 = \frac\pi{12}

(c) Similarly, when raising a complex number to any power, you raise the modulus to that power, and then multiply the argument for that value.

(z_1)^1^2=[4e^{-i\frac \pi6}]^1^2=4^1^2\cdot (e^{-i\frac \pi6})^1^2=2^2^4\cdot e^{-i(12)\frac\pi6}\\=2^2^4 e^{-i\cdot2\pi}=2^2^4

Now, in the last step I've used the fact that e^{i(2k\pi+x)} = e^i^x ; k\in \mathbb Z, or in other words, the complex exponential is periodic with 2\pi as a period, same as sine and cosine. You can further compute that power of two with the help of a calculator, it is around 16 million, or leave it as is.

7 0
2 years ago
Solve the equation graphically: √ x = - x.
Nikolay [14]
Sqrt[x] = -x   
x= x ^ 2  
x - x^2 = 0
-x(x-1)=0
x(x-1)=0
x = 1 or x = 0
sqrt 1 isn not equal to 0

x= 0

6 0
4 years ago
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