Answer:
35
Step-by-step explanation:
Answer:
56.39 nm
Step-by-step explanation:
In order to have constructive interference total optical path difference should be an integral number of wavelengths (crest and crest should be interfered). Therefore the constructive interference condition for soap film can be written as,

where λ is the wavelength of light and n is the refractive index of soap film, t is the thickness of the film, and m=0,1,2 ...
Please note that here we include an additional 1/2λ phase shift due to reflection from air-soap interface, because refractive index of latter is higher.
In order to have its longest constructive reflection at the red end (700 nm)

Here we take m=0.
Similarly for the constructive reflection at the blue end (400 nm)

Hence the thickness difference should be

B(b^2+49)
There you go I found this on math papa.com
Looking at y=-%285%2F2%29x we can see that the equation is in slope-intercept form y=mx%2Bb where the slope is m=-5%2F2 and the y-intercept is b=0 note: y=-%285%2F2%29x really looks like y=-%285%2F2%29x%2B0
Since b=0 this tells us that the y-intercept is .Remember the y-intercept is the point where the graph intersects with the y-axis
So we have one point
Now since the slope is comprised of the "rise" over the "run" this means
slope=rise%2Frun
Also, because the slope is -5%2F2, this means:
rise%2Frun=-5%2F2
which shows us that the rise is -5 and the run is 2. This means that to go from point to point, we can go down 5 and over 2
So starting at , go down 5 units
and to the right 2 units to get to the next point
Now draw a line through these points to graph y=-%285%2F2%29x
So this is the graph of y=-%285%2F2%29x through the points
Hope this helps
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